In a laboratory you measure the decay rate of a sample of radioactive carbon. You write down the following measurements: $$\begin{array}{lrrrrrrr} \hline \text { Time (min) } & 0 & 15 & 30 & 45 & 60 & 75 & 90 \\\ \text { Decays/s } & 405 & 237 & 140 & 90 & 55 & 32 & 19 \\\ \hline \end{array}$$ (a) Plot the decays per second versus time. (b) Plot the natural logarithm of the decays per second versus the time. Why might the presentation of the data in this form be useful?

Short Answer

Expert verified
Answer: Presenting the data in the form of ln(decays/s) versus time can be useful because it transforms the exponential decay curve into a linear curve, allowing for easier understanding of the relationship between decay rate and elapsed time. This linear representation also aids in deriving parameters such as the decay constant or half-life.

Step by step solution

01

Convert time to seconds

Since the decay rate is given in decays per second, we should convert the time from minutes to seconds for better consistency. To do this, multiply each time value by 60.
02

Create a scatter plot for the decay rate against time

Now, you can create a scatter plot using the converted time values (in seconds) and the corresponding decay rates. Label the x-axis as "Time (s)" and the y-axis as "Decays/s".
03

Calculate the natural logarithm of the decay rate

To plot the natural logarithm of the decay rate, use the natural logarithm function (ln) to find the ln(decays/s) for each time point in the dataset.
04

Create a scatter plot for the natural logarithm of the decay rate against time

Now, create a new scatter plot using the same time values (in seconds) but with the ln(decays/s) values you calculated in step 3. Label the x-axis as "Time (s)" and the y-axis as "ln(Decays/s)".
05

Discuss the usefulness of plotting ln(decays/s) vs. time

The presentation of this data in the form of ln(decays/s) versus time may be useful because radioactive decay generally follows an exponential decay process. By taking the natural logarithm of the decay rate, we can transform the exponential decay curve into a linear curve, which can help us better understand the relationship between decay rate and elapsed time. Additionally, in a linear curve, we can more easily derive parameters such as the decay constant or half-life.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Kepler's law of planetary motion says that the square of the period of a planet \(\left(T^{2}\right)\) is proportional to the cube of the distance of the planet from the Sun \(\left(r^{3}\right) .\) Mars is about twice as far from the Sun as Venus. How does the period of Mars compare with the period of Venus?
The record blue whale in Problem 68 had a mass of $1.9 \times 10^{5} \mathrm{kg} .\( Assuming that its average density was \)0.85 \mathrm{g} / \mathrm{cm}^{3},$ as has been measured for other blue whales, what was the volume of the whale in cubic meters \(\left(\mathrm{m}^{3}\right) ?\) (Average density is the ratio of mass to volume.)
A sprinter can run at a top speed of 0.32 miles per minute. Express her speed in (a) \(\mathrm{m} / \mathrm{s}\) and (b) \(\mathrm{mi} / \mathrm{h}\).
The gardener is told that he must increase the height of his fences \(37 \%\) if he wants to keep the deer from jumping in to eat the foliage and blossoms. If the current fence is \(1.8 \mathrm{m}\) high, how high will the new fence be?
You are given these approximate measurements: (a) the radius of Earth is $6 \times 10^{6} \mathrm{m},\( (b) the length of a human body is \)6 \mathrm{ft},(\mathrm{c})\( a cell's diameter is \)10^{-6} \mathrm{m},$ (d) the width of the hemoglobin molecule is \(3 \times 10^{-9} \mathrm{m},\) and (e) the distance between two atoms (carbon and nitrogen) is $3 \times 10^{-10} \mathrm{m} .$ Write these measurements in the simplest possible metric prefix forms (in either nm, Mm, \(\mu \mathrm{m}\), or whatever works best).
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free