The "scale" of a certain map is \(1 / 10000 .\) This means the length of, say, a road as represented on the map is \(1 / 10000\) the actual length of the road. What is the ratio of the area of a park as represented on the map to the actual area of the park? (tutorial: scaling)

Short Answer

Expert verified
Answer: The ratio of the area of a park as represented on the map to the actual area of the park is 1:100000000.

Step by step solution

01

Identify the scaling factor of length and width

In this case, the scaling factor for both length and width of the park between the map and the actual area is 1:10000.
02

Calculate the area scaling factor

To find the ratio of the areas, we need to square the scaling factor since we need to scale the length and width together (Area = Length * Width). If the scaling factor is 1:10000 for length and width, then for area, it would be \((1/10000)^2\).
03

Simplify the area scaling factor

Now, let's simplify the area scaling factor by squaring the ratio \((1/10000)^2\): \((1/10000)^2 = 1/100000000\)
04

Write the final ratio

The ratio of the area of a park as represented on the map to the actual area of the park is 1:100000000.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The weight \(W\) of an object is given by \(W=m g,\) where \(m\) is the object's mass and \(g\) is the gravitational field strength. The SI unit of field strength \(g\), expressed in SI base units, is \(\mathrm{m} / \mathrm{s}^{2} .\) What is the SI unit for weight, expressed in base units?
The speed of ocean waves depends on their wavelength \(\lambda\) (measured in meters) and the gravitational field strength \(g\) (measured in $\mathrm{m} / \mathrm{s}^{2}$ ) in this way: $$ v=K \lambda^{p} g^{q} $$ where \(K\) is a dimensionless constant. Find the values of the exponents \(p\) and \(q\)
You are given these approximate measurements: (a) the radius of Earth is $6 \times 10^{6} \mathrm{m},\( (b) the length of a human body is \)6 \mathrm{ft},(\mathrm{c})\( a cell's diameter is \)10^{-6} \mathrm{m},$ (d) the width of the hemoglobin molecule is \(3 \times 10^{-9} \mathrm{m},\) and (e) the distance between two atoms (carbon and nitrogen) is $3 \times 10^{-10} \mathrm{m} .$ Write these measurements in the simplest possible metric prefix forms (in either nm, Mm, \(\mu \mathrm{m}\), or whatever works best).
The average speed of a nitrogen molecule in air is proportional to the square root of the temperature in kelvins \((\mathrm{K}) .\) If the average speed is \(475 \mathrm{m} / \mathrm{s}\) on a warm summer day (temperature $=300.0 \mathrm{K}\( ), what is the average speed on a cold winter day \)(250.0 \mathrm{K}) ?$
An object moving at constant speed \(v\) around a circle of radius \(r\) has an acceleration \(a\) directed toward the center of the circle. The SI unit of acceleration is \(\mathrm{m} / \mathrm{s}^{2} .\) (a) Use dimensional analysis to find \(a\) as a function of \(v\) and \(r\) (b) If the speed is increased $10.0 \%,$ by what percentage does the radial acceleration increase?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free