A pendulum of length \(120 \mathrm{cm}\) swings with an amplitude of $2.0 \mathrm{cm} .\( Its mechanical energy is \)5.0 \mathrm{mJ} .$ What is the mechanical energy of the same pendulum when it swings with an amplitude of \(3.0 \mathrm{cm} ?\)

Short Answer

Expert verified
Answer: The mechanical energy of the pendulum when its amplitude changes to 3.0 cm is 7.5 mJ.

Step by step solution

01

Understand the relationship between amplitude and mechanical energy

The mechanical energy of a simple pendulum is the sum of its kinetic and potential energy at any point in its swing. At the maximum amplitude, the pendulum has only potential energy (when it is momentarily at rest) which can be written as: \(E_{p} = mgh\) However, at the new amplitude, this potential energy increases, and the mechanical energy should also increase proportionally. Hence, we can write the relationship between the amplitude and mechanical energy as: \(E_{1} \propto h_1\) and \(E_{2} \propto h_2\) Dividing the two equations, we get: \(\frac{E_2}{E_1} = \frac{h_2}{h_1}\)
02

Determine the changes in amplitude

The initial amplitude \(h_1 = 2.0 \, \mathrm{cm}\) and the final amplitude \(h_2 = 3.0 \, \mathrm{cm}\). The change in amplitude is: \(\Delta h = h_2 - h_1 = 3.0 \, \mathrm{cm} - 2.0 \, \mathrm{cm} = 1.0 \, \mathrm{cm}\)
03

Find the ratio of the new amplitude to the old amplitude

Divide the final amplitude \(h_2\) by the initial amplitude \(h_1\): \(\frac{h_2}{h_1} = \frac{3.0 \, \mathrm{cm}}{2.0 \, \mathrm{cm}}\)
04

Calculate the new mechanical energy

We know the initial mechanical energy \(E_1 = 5.0 \, \mathrm{mJ}\), and we just found the ratio \(\frac{h_2}{h_1}\). Now, multiply \(E_1\) by the ratio \(\frac{h_2}{h_1}\) to get the new mechanical energy \(E_2\): \(E_2 = E_1 \cdot \frac{h_2}{h_1} = 5.0 \, \mathrm{mJ} \cdot \frac{3.0 \, \mathrm{cm}}{2.0 \, \mathrm{cm}}\) \(E_2 = 7.5 \, \mathrm{mJ}\) So, the mechanical energy of the pendulum when it swings with an amplitude of \(3.0 \, \mathrm{cm}\) is \(7.5 \, \mathrm{mJ}\).

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