What is the wavelength of the radio waves transmitted by an FM station at 90 MHz? (Radio waves travel at \(3.0 \times 10^{8} \mathrm{m} / \mathrm{s} .\)

Short Answer

Expert verified
Answer: The wavelength of the radio waves transmitted by an FM station at 90 MHz is 3.33 meters.

Step by step solution

01

Write down the wave speed formula

The wave speed formula is: speed = frequency × wavelength or v = f × λ Where v is the speed of the radio waves, f is the frequency of the radio waves, and λ is the wavelength of the radio waves.
02

Rearrange the formula to solve for wavelength

To find the wavelength, we need to rearrange the equation: λ = v / f
03

Convert the given frequency to Hz

The frequency is given in MHz, which is megahertz. We need to convert it to hertz (Hz) for our calculations: 90 MHz = 90 × 10^6 Hz
04

Plug in given values and solve for wavelength

Now, we can plug in the values for the speed of radio waves (v = 3.0 × 10^8 m/s) and frequency (f = 90 × 10^6 Hz) into the rearranged equation: λ = (3.0 × 10^8 m/s) / (90 × 10^6 Hz)
05

Calculate the wavelength

Now, we can perform the calculation: λ = (3.0 × 10^8 m/s) / (90 × 10^6 Hz) = (3.0 / 90) × 10^2 m = 0.033 × 10^2 m = 3.33 m The wavelength of the radio waves transmitted by an FM station at 90 MHz is 3.33 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A transverse wave on a string is described by the equation $y(x, t)=(2.20 \mathrm{cm}) \sin [(130 \mathrm{rad} / \mathrm{s}) t+(15 \mathrm{rad} / \mathrm{m}) x].$ (a) What is the maximum transverse speed of a point on the string? (b) What is the maximum transverse acceleration of a point on the string? (c) How fast does the wave move along the string? (d) Why is your answer to (c) different from the answer to (a)?
A metal guitar string has a linear mass density of $\mu=3.20 \mathrm{g} / \mathrm{m} .$ What is the speed of transverse waves on this string when its tension is \(90.0 \mathrm{N} ?\)
Light visible to humans consists of electromagnetic waves with wavelengths (in air) in the range \(400-700 \mathrm{nm}\) $\left(4.0 \times 10^{-7} \mathrm{m} \text { to } 7.0 \times 10^{-7} \mathrm{m}\right) .$ The speed of light in air is \(3.0 \times 10^{8} \mathrm{m} / \mathrm{s} .\) What are the frequencies of electromagnetic waves that are visible?
Deep-water waves are dispersive (their wave speed depends on the wavelength). The restoring force is provided by gravity. Using dimensional analysis, find out how the speed of deep-water waves depends on wavelength \(\lambda\), assuming that \(\lambda\) and \(g\) are the only relevant quantities. (Mass density does not enter into the expression because the restoring force, arising from the weight of the water, is itself proportional to the mass density.)
Using graph paper, sketch two identical sine waves of amplitude $4.0 \mathrm{cm}\( that differ in phase by (a) \)\pi / 3$ rad \(\left(60^{\circ}\right)\) and (b) \(\pi / 2\) rad \(\left(90^{\circ}\right) .\) Find the amplitude of the superposition of the two waves in each case.
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free