A longitudinal wave has a wavelength of \(10 \mathrm{cm}\) and an amplitude of \(5.0 \mathrm{cm}\) and travels in the \(y\) -direction. The wave speed in this medium is \(80 \mathrm{cm} / \mathrm{s},\) (a) Describe the motion of a particle in the medium as the wave travels through the medium. (b) How would your answer differ if the wave were transverse instead?

Short Answer

Expert verified
Answer: If the wave was a transverse wave, the particles in the medium would move perpendicular to the direction of the wave propagation, up and down along the x-axis, instead of parallel to the wave propagation like in a longitudinal wave.

Step by step solution

01

Part (a): Describing the motion of a particle in the medium for a longitudinal wave

In a longitudinal wave, particles move parallel to the direction of the wave's propagation. In this case, the wave is moving in the y-direction with a wavelength of 10 cm and an amplitude of 5.0 cm. The motion of the particle in the medium can be described using the equation: $$ y(t) = A \cos (kx - \omega t + \phi) $$ where \(y(t)\): Displacement of the particle \(A\): Amplitude \(k\): Wave number (equal to \(2\pi / \lambda\), \(\lambda\) being the wavelength) \(\omega\): Angular frequency (equal to \(2\pi / T\), T being the period) \(t\): Time \(x\): Position of the particle \(\phi\): Phase constant Using the given values and the speed of the wave \(v = 80 \mathrm{cm}/s\), we can find the period (\(T\)) and frequency (\(f\)) of the wave: $$ T = \frac{\lambda}{v} = \frac{10 cm}{80 cm/s} = 0.125 s $$ $$ f = \frac{1}{T} = 8 Hz $$ Now we can find the angular frequency \(\omega\): $$ \omega = 2\pi f = 16 \pi rad/s $$ And the wave number \(k\): $$ k = \frac{2\pi}{\lambda} = \frac{2\pi}{10 cm} = \frac{\pi}{5} rad/cm $$ Now we can write the motion of the particle as: $$ y(t) = 5.0 \cos \left(\frac{\pi}{5}x - 16 \pi t + \phi \right) $$ This equation describes the displacement of a particle in the medium as the longitudinal wave travels through it.
02

Part (b): Comparison of motion with a transverse wave

If the wave was a transverse wave instead of a longitudinal wave, the motion of particles in the medium would be perpendicular to the direction of the wave propagation (y-direction). The particles would move up and down along the x axis instead. The equation representing the motion of a particle in the medium would still be the same, but it would now represent movement in the x direction instead of in the y-direction: $$ x(t) = 5.0 \cos \left(\frac{\pi}{5}y - 16 \pi t + \phi \right) $$ In summary, the main difference in motion between longitudinal and transverse waves is the direction in which the particles in the medium move: parallel to the direction of wave propagation for longitudinal waves, and perpendicular to the direction of wave propagation for transverse waves.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two coherent sound waves have intensities of $0.040 \mathrm{W} / \mathrm{m}^{2}\( and \)0.090 \mathrm{W} / \mathrm{m}^{2}$ where you are listening. (a) If the waves interfere constructively, what is the intensity that you hear? (b) What if they interfere destructively? (c) If they were incoherent, what would be the intensity? [Hint: If your answers are correct, then (c) is the average of (a) and (b).]
Write an equation for a sine wave with amplitude \(0.120 \mathrm{m}\) wavelength \(0.300 \mathrm{m},\) and wave speed \(6.40 \mathrm{m} / \mathrm{s}\) traveling in the \(-x\) -direction.
A metal guitar string has a linear mass density of $\mu=3.20 \mathrm{g} / \mathrm{m} .$ What is the speed of transverse waves on this string when its tension is \(90.0 \mathrm{N} ?\)
A traveling sine wave is the result of the superposition of two other sine waves with equal amplitudes, wavelengths, and frequencies. The two component waves each have amplitude \(5.00 \mathrm{cm} .\) If the superposition wave has amplitude \(6.69 \mathrm{cm},\) what is the phase difference \(\phi\) between the component waves? [Hint: Let \(y_{1}=A \sin (\omega t+k x)\) and $y_{2}=A \sin (\omega t+k x-\phi) .$ Make use of the trigonometric identity (Appendix A.7) for \(\sin \alpha+\sin \beta\) when finding \(y=y_{1}+y_{2}\) and identify the new amplitude in terms of the original amplitude. \(]\)
A sound wave with intensity \(25 \mathrm{mW} / \mathrm{m}^{2}\) interferes destructively with a sound wave that has an intensity of $28 \mathrm{mW} / \mathrm{m}^{2} .$ What is the intensity of the superposition of the two?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free