Find the speed of sound in mercury, which has a bulk modulus of $2.8 \times 10^{10} \mathrm{Pa}\( and a density of \)1.36 \times\( \)10^{4} \mathrm{kg} / \mathrm{m}^{3}.$

Short Answer

Expert verified
Answer: The speed of sound in mercury is approximately \(1443.29 \mathrm{m/s}\).

Step by step solution

01

Write down the given information

We are given the following information: Bulk modulus, \(B = 2.8 \times 10^{10} \mathrm{Pa}\) Density, \(ρ = 1.36 \times 10^{4} \mathrm{kg/m}^{3}\)
02

Use the formula for the speed of sound

We will use the formula for calculating the speed of sound in a material: \(v = \sqrt{\dfrac{B}{ρ}}\)
03

Substitute the values into the formula

Substitute the values of the bulk modulus and the density into the formula: \(v = \sqrt{\dfrac{2.8 \times 10^{10} \mathrm{Pa}}{1.36 \times 10^{4} \mathrm{kg/m}^{3}}}\)
04

Calculate the speed of sound

Now, perform the calculations to find the speed of sound in mercury: \(v = \sqrt{\dfrac{2.8 \times 10^{10}}{1.36 \times 10^{4}}} \mathrm{m/s}\) \(v \approx 1443.29 \mathrm{m/s}\) The speed of sound in mercury is approximately \(1443.29 \mathrm{m/s}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A certain pipe has resonant frequencies of \(234 \mathrm{Hz}\) $390 \mathrm{Hz},\( and \)546 \mathrm{Hz},$ with no other resonant frequencies between these values. (a) Is this a pipe open at both ends or closed at one end? (b) What is the fundamental frequency of this pipe? (c) How long is this pipe?
Some bats determine their distance to an object by detecting the difference in intensity between cchoes.(a) If intensity falls off at a rate that is inversely proportional to the distance squared, show that the echo intensity is inversely proportional to the fourth power of distance. (b) The bat was originally \(0.60 \mathrm{m}\) from one object and \(1.10 \mathrm{m}\) from another. After flying closer, it is now \(0.50 \mathrm{m}\) from the first and at \(1.00 \mathrm{m}\) from the second object. What is the percentage increase in the intensity of the ccho from each object?
At a baseball game, a spectator is \(60.0 \mathrm{m}\) away from the batter. How long does it take the sound of the bat connecting with the ball to travel to the spectator's ears? The air temperature is \(27.0^{\circ} \mathrm{C}\)
Two tuning forks, \(A\) and \(B\), excite the next-to-lowest resonant frequency in two air columns of the same length, but A's column is closed at one end and B's column is open at both ends. What is the ratio of A's frequency to B's frequency?
(a) What should be the length of an organ pipe, closed at one end, if the fundamental frequency is to be \(261.5 \mathrm{Hz} ?\) (b) What is the fundamental frequency of the organ pipe of part (a) if the temperature drops to \(0.0^{\circ} \mathrm{C} ?\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free