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Chapter 13: Problem 2

The temperature at which liquid nitrogen boils (at atmospheric pressure) is \(77 \mathrm{K}\). Express this temperature in (a) \(^{\circ} \mathrm{C}\) and (b) \(^{\circ} \mathrm{F}\).

Short Answer

Expert verified
Answer: The boiling point temperatures of liquid nitrogen are -196.15°C and -320.67°F.

Step by step solution

01

Write down the given temperature in Kelvin

The given temperature in Kelvin is \(77 \mathrm{K}\).
02

Convert the temperature to Celsius

Use the formula: \(^{\circ}\mathrm{C} = \mathrm{K} - 273.15\). \(^{\circ}\mathrm{C} = 77 - 273.15 = -196.15 ^{\circ}\mathrm{C}\)
03

Convert the temperature to Fahrenheit

Use the formula: \(^{\circ}\mathrm{F} = \frac{9}{5} (^{\circ}\mathrm{C}) + 32\). \(^{\circ}\mathrm{F} = \frac{9}{5}(-196.15) + 32 = -320.67 ^{\circ}\mathrm{F}\) The temperature at which liquid nitrogen boils is \(-196.15 ^{\circ}\mathrm{C}\) and \(-320.67 ^{\circ}\mathrm{F}\).

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