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Chapter 13: Problem 28

Find the molar mass of ammonia (NH \(_{3}\) ).

Short Answer

Expert verified
Answer: The molar mass of ammonia (NH\(_{3}\)) is 17.034 g/mol.

Step by step solution

01

Determine the molar mass of Nitrogen (N)

Find the atomic mass of Nitrogen on the periodic table. The atomic mass of Nitrogen is approximately 14.01 amu. The molar mass of Nitrogen is 14.01 g/mol.
02

Determine the molar mass of Hydrogen (H)

Find the atomic mass of Hydrogen on the periodic table. The atomic mass of Hydrogen is approximately 1.008 amu. The molar mass of Hydrogen is 1.008 g/mol.
03

Calculate the molar mass of NH\(_{3}\)

To calculate the molar mass of ammonia (NH\(_{3}\)), add the molar mass of Nitrogen (N) to three times the molar mass of Hydrogen (H), as there are three Hydrogen atoms in the ammonia molecule: Molar mass of NH\(_{3}\) = Molar mass of N + (3 × Molar mass of H) Molar mass of NH\(_{3}\) = 14.01 g/mol + (3 × 1.008 g/mol) Molar mass of NH\(_{3}\) = 14.01 g/mol + 3.024 g/mol = 17.034 g/mol

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Most popular questions from this chapter

A \(10.0-\mathrm{L}\) vessel contains \(12 \mathrm{g}\) of \(\mathrm{N}_{2}\) gas at \(20^{\circ} \mathrm{C}\) (a) Estimate the nearest-neighbor distance. (b) Is the gas dilute? [Hint: Compare the nearest-neighbor distance to the diameter of an \(\left.\mathrm{N}_{2} \text { molecule, about } 0.3 \mathrm{nm} .\right]\)
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What is the mass of one gold atom in kilograms?
The inner tube of a Pyrex glass mercury thermometer has a diameter of $0.120 \mathrm{mm} .\( The bulb at the bottom of the thermometer contains \)0.200 \mathrm{cm}^{3}$ of mercury. How far will the thread of mercury move for a change of \(1.00^{\circ} \mathrm{C} ?\) Remember to take into account the expansion of the glass. (W) tutorial thermometer)
Agnes Pockels \((1862-1935)\) was able to determine Avogadro's number using only a few household chemicals, in particular oleic acid, whose formula is \(\mathrm{C}_{18} \mathrm{H}_{34} \mathrm{O}_{2}\) (a) What is the molar mass of this acid? (b) The mass of one drop of oleic acid is \(2.3 \times 10^{-5} \mathrm{g}\) and the volume is $2.6 \times 10^{-5} \mathrm{cm}^{3} .$ How many moles of oleic acid are there in one drop? (c) Now all Pockels needed was to find the number of molecules of oleic acid. Luckily, when oleic acid is spread out on water, it lines up in a layer one molecule thick. If the base of the molecule of oleic acid is a square of side \(d\), the height of the molecule is known to be \(7 d .\) Pockels spread out one drop of oleic acid on some water, and measured the area to be \(70.0 \mathrm{cm}^{2}\) Using the volume and the area of oleic acid, what is \(d ?\) (d) If we assume that this film is one molecule thick, how many molecules of oleic acid are there in the drop? (e) What value does this give you for Avogadro's number?
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