Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 14: Problem 66

If the maximum intensity of radiation for a blackbody is found at $2.65 \mu \mathrm{m},$ what is the temperature of the radiating body?

Short Answer

Expert verified
Answer: The temperature of the radiating body is approximately 1094.34 K.

Step by step solution

01

Convert wavelength to meters

We are given \(\lambda_{max}\) in micrometers. Let's convert it to meters: $$\lambda_{max} = 2.65 \, \mu \mathrm{m} = 2.65 \times 10^{-6} \, \mathrm{m}$$
02

Rearrange Wien's Displacement Law formula

Let's rearrange Wien's Displacement Law formula to find the temperature \(T\): $$ T = \frac{b}{\lambda_{max}}$$
03

Plug in the values and solve for T

Now we will plug in the values for \(\lambda_{max}\) and \(b\) and solve for the temperature: $$ T = \frac{2.898 \times 10^{-3} \, \text{m K}}{2.65 \times 10^{-6} \, \mathrm{m}}$$ Divide \(2.898 \times 10^{-3}\) by \(2.65 \times 10^{-6}\) to find the temperature: $$ T \approx 1094.34 \, \text{K}$$ So, the temperature of the radiating body is approximately \(1094.34 \, \text{K}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cylinder contains 250 L of hydrogen gas \(\left(\mathrm{H}_{2}\right)\) at \(0.0^{\circ} \mathrm{C}\) and a pressure of 10.0 atm. How much energy is required to raise the temperature of this gas to \(25.0^{\circ} \mathrm{C} ?\)
An experiment is conducted with a basic Joule apparatus, where a mass is allowed to descend by \(1.25 \mathrm{m}\) and rotate paddles within an insulated container of water. There are several different sizes of descending masses to choose among. If the investigator wishes to deliver \(1.00 \mathrm{kJ}\) to the water within the insulated container after 30.0 descents, what descending mass value should be used?
A metal rod with a diameter of \(2.30 \mathrm{cm}\) and length of $1.10 \mathrm{m}\( has one end immersed in ice at \)32.0^{\circ} \mathrm{F}$ and the other end in boiling water at \(212^{\circ} \mathrm{F}\). If the ice melts at a rate of 1.32 g every 175 s, what is the thermal conductivity of this metal? Identify the metal. Assume there is no heat lost to the surrounding air.
It requires \(17.10 \mathrm{kJ}\) to melt \(1.00 \times 10^{2} \mathrm{g}\) of urethane $\left[\mathrm{CO}_{2}\left(\mathrm{NH}_{2}\right) \mathrm{C}_{2} \mathrm{H}_{5}\right]\( at \)48.7^{\circ} \mathrm{C} .$ What is the latent heat of fusion of urethane in \(\mathrm{kJ} / \mathrm{mol} ?\)
Compute the heat of fusion of a substance from these data: \(31.15 \mathrm{kJ}\) will change \(0.500 \mathrm{kg}\) of the solid at \(21^{\circ} \mathrm{C}\) to liquid at \(327^{\circ} \mathrm{C},\) the melting point. The specific heat of the solid is \(0.129 \mathrm{kJ} /(\mathrm{kg} \cdot \mathrm{K})\).
See all solutions

Recommended explanations on Physics Textbooks

Work Energy and Power

Read Explanation

Nuclear Physics

Read Explanation

Wave Optics

Read Explanation

Turning Points in Physics

Read Explanation

Physical Quantities And Units

Read Explanation

Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free