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Chapter 14: Problem 80

Many species cool themselves by sweating, because as the sweat evaporates, heat is given up to the surroundings. A human exercising strenuously has an evaporative heat loss rate of about \(650 \mathrm{W}\). If a person exercises strenuously for 30.0 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is \(2430 \mathrm{J} / \mathrm{g}\) at normal skin temperature.

Short Answer

Expert verified
Answer: The person must drink approximately 481.48 g (or 0.481 L) of water to replenish the fluid loss.

Step by step solution

01

Calculate the total heat lost

To find the total heat lost, we'll use the formula: Total Heat Lost = Evaporative Heat Loss Rate × Time We are given Evaporative Heat Loss Rate = 650 W and Time = 30 min (which needs to be converted to seconds). So, Time in seconds = 30 × 60 = 1800 s. Now, we can calculate the total heat lost: Total Heat Lost = 650 W × 1800 s = 1170000 J (Joules)
02

Calculate the amount of water needed

Now that we have the total heat lost, we can use the heat of vaporization to find out the amount of water needed. We are given the heat of vaporization of water as 2430 J/g. So, we'll use the formula: Amount of Water = Total Heat Lost / Heat of Vaporization of Water Amount of Water = 1170000 J / (2430 J/g) = 481.481481 g To replenish the fluid loss, the person must drink approximately 481.48 g (or 0.481 L) of water.

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Most popular questions from this chapter

The thermal conductivity of the fur (including the skin) of a male Husky dog is \(0.026 \mathrm{W} /(\mathrm{m} \cdot \mathrm{K}) .\) The dog's heat output is measured to be \(51 \mathrm{W}\), its internal temperature is $38^{\circ} \mathrm{C},\( its surface area is \)1.31 \mathrm{m}^{2},$ and the thickness of the fur is \(5.0 \mathrm{cm} .\) How cold can the outside temperature be before the dog must increase its heat output?
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