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Chapter 15: Problem 23

How much heat does a heat pump with a coefficient of performance of 3.0 deliver when supplied with \(1.00 \mathrm{kJ}\) of electricity?

Short Answer

Expert verified
Answer: The heat pump delivers 3.00 kJ of heat when supplied with 1.00 kJ of electricity.

Step by step solution

01

Understand the coefficient of performance of a heat pump formula

The coefficient of performance (COP) for a heat pump can be calculated using this formula: COP = Q_H / W, where Q_H is the heat delivered by the heat pump, and W is the work input (in our case, 1.00 kJ of electricity).
02

Use the given values to find the heat delivered

We are given the coefficient of performance (COP) as 3.0 and the work input (W) as 1.00 kJ. We can now use these values in the formula to find the heat delivered (Q_H): COP = Q_H / W => Q_H = COP * W
03

Calculate the heat delivered

Substitute the given values into the equation: Q_H = (3.0) * (1.00 kJ) Q_H = 3.00 kJ The heat pump delivers 3.00 kJ of heat when supplied with 1.00 kJ of electricity.

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Most popular questions from this chapter

(a) Calculate the efficiency of a reversible engine that operates between the temperatures \(600.0^{\circ} \mathrm{C}\) and \(300.0^{\circ} \mathrm{C} .\) (b) If the engine absorbs \(420.0 \mathrm{kJ}\) of heat from the hot reservoir, how much does it exhaust to the cold reservoir?
If the pressure on a fish increases from 1.1 to 1.2 atm, its swim bladder decreases in volume from \(8.16 \mathrm{mL}\) to \(7.48 \mathrm{mL}\) while the temperature of the air inside remains constant. How much work is done on the air in the bladder?
The internal energy of a system increases by 400 J while \(500 \mathrm{J}\) of work are performed on it. What was the heat flow into or out of the system?
A reversible engine with an efficiency of \(30.0 \%\) has $T_{\mathrm{C}}=310.0 \mathrm{K} .\( (a) What is \)T_{\mathrm{H}} ?$ (b) How much heat is exhausted for every \(0.100 \mathrm{kJ}\) of work done?
For a reversible engine, will you obtain a better efficiency by increasing the high-temperature reservoir by an amount \(\Delta T\) or decreasing the low- temperature reservoir by the same amount \(\Delta T ?\)
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