The internal energy of a system increases by 400 J while \(500 \mathrm{J}\) of work are performed on it. What was the heat flow into or out of the system?

Short Answer

Expert verified
Answer: The heat flow into the system is 900 J.

Step by step solution

01

Read the problem and gather information

In this problem, we are given: - The internal energy increase of the system: \(\Delta U = 400 \,\text{J}\) - The work done on the system: \(W = 500\, \text{J}\) Our goal is to find the heat flow into or out of the system (\(Q\)).
02

Apply the first law of thermodynamics

We will use the formula for the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system: \(\Delta U = Q - W\)
03

Substitute the given values

Let's substitute the given values of \(\Delta U\) and \(W\) into the equation: \(400 \,\text{J} = Q - 500 \,\text{J}\)
04

Solve for Q

Now, we just need to solve for \(Q\): \(Q = 400 \,\text{J} + 500 \,\text{J} = 900\, \text{J}\) So, the heat flow into the system is \(900 \,\text{J}\).

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