Estimate the entropy change of \(850 \mathrm{g}\) of water when it is heated from \(20.0^{\circ} \mathrm{C}\) to \(50.0^{\circ} \mathrm{C} .\) [Hint: Assume that the heat flows into the water at an average temperature. \(]\)

Short Answer

Expert verified
The estimated entropy change is approximately 349 J/K when 850g of water is heated from 20.0°C to 50.0°C.

Step by step solution

01

Convert temperatures to Kelvin

First, we need to convert the given temperatures from Celsius to Kelvin. To do this, we will add 273.15 to each Celsius temperature: \(T_1 = 20.0 + 273.15 = 293.15 \mathrm{K}\) \(T_2 = 50.0 + 273.15 = 323.15 \mathrm{K}\)
02

Calculate the average temperature

We will now calculate the average temperature during the heating process: \(T_\text{avg} = \frac{T_1 + T_2}{2} = \frac{293.15 + 323.15}{2} = 308.15 \mathrm{K}\)
03

Calculate the entropy change

We can now calculate the entropy change using the formula: \(\Delta S = mC\log \frac{T_2}{T_1} = (850 \mathrm{g})(4.18 \mathrm{J / g \cdot K})\log \frac{323.15 \mathrm{K}}{293.15 \mathrm{K}}\) Now, compute the logarithm and multiply the resulting value with the mass and specific heat capacity: \(\Delta S = (850 \mathrm{g})(4.18 \mathrm{J / g \cdot K})(0.0970) = 348.803 \mathrm{J/K}\)
04

Round the result

Finally, we will round the result to an appropriate number of significant figures (three): \(\Delta S \approx 349 \mathrm{J/K}\) The estimated entropy change of 850g of water when it is heated from \(20.0^{\circ} \mathrm{C}\) to \(50.0^{\circ} \mathrm{C}\) is approximately 349 J/K.

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