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Chapter 16: Problem 1

Find the total positive charge of all the protons in \(1.0 \mathrm{mol}\) of water.

Short Answer

Expert verified
Answer: The total positive charge of all the protons in 1.0 mol of water is approximately \(1.93\times10^{6}\) coulombs.

Step by step solution

01

Determine the number of protons in one water molecule

A water molecule has the chemical formula H₂O, which means it consists of two hydrogen atoms and one oxygen atom. Since each hydrogen atom contains 1 proton, there are 2 protons in a single water molecule.
02

Determine the number of molecules in 1.0 mol of water

One mole of any substance contains Avogadro's number (approximately \(6.022\times10^{23}\)) of particles (atoms, molecules, ions, etc.). Therefore, there are about \(6.022\times10^{23}\) water molecules in 1.0 mol of water.
03

Find the total number of protons in 1.0 mol of water

To determine the total number of protons in 1.0 mol of water, we need to multiply the number of protons in a single water molecule by the number of water molecules in 1.0 mol of water: Total protons \(= 2\) protons/water molecule \(\times 6.022\times10^{23}\) water molecules/mol \(= 1.2044\times10^{24}\) protons
04

Find the total positive charge of all the protons

The elementary charge of a single proton is approximately \(1.602\times10^{-19}\) coulombs. Therefore, to find the total positive charge of all the protons, we multiply the total number of protons by the elementary charge of a proton: Total positive charge \(= 1.2044\times10^{24}\) protons \(\times 1.602\times10^{-19}\) coulombs/proton \(\approx 1.93\times10^{6}\) coulombs So, the total positive charge of all the protons in 1.0 mol of water is about \(1.93\times10^{6}\) coulombs.

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Most popular questions from this chapter

Two otherwise identical conducting spheres carry charges of $+5.0 \mu \mathrm{C}\( and \)-1.0 \mu \mathrm{C} .$ They are initially a large distance \(L\) apart. The spheres are brought together, touched together, and then returned to their original separation \(L\). What is the ratio of the magnitude of the force on either sphere after they are touched to that before they were touched?
What are the magnitude and direction of the electric field midway between two point charges, \(-15 \mu \mathrm{C}\) and \(+12 \mu \mathrm{C},\) that are $8.0 \mathrm{cm}$ apart?
Two point charges, \(q_{1}=+20.0 \mathrm{nC}\) and \(q_{2}=+10.0 \mathrm{nC},\) are located on the \(x\) -axis at \(x=0\) and \(x=1.00 \mathrm{m},\) respectively. Where on the \(x\) -axis is the electric field equal to zero?
The electric field across a cellular membrane is $1.0 \times 10^{7} \mathrm{N} / \mathrm{C}$ directed into the cell. (a) If a pore opens, which way do sodium ions (Na") flow- into the cell or out of the cell? (b) What is the magnitude of the electric force on the sodium ion? The charge on the sodium ion is \(+e\)
Sketch the electric field lines near two isolated and equal (a) positive point charges and (b) negative point charges. Include arrowheads to show the field directions.
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