A shark is able to detect the presence of electric fields as small as $1.0 \mu \mathrm{V} / \mathrm{m} .$ To get an idea of the magnitude of this field, suppose you have a parallel plate capacitor connected to a 1.5 - \(V\) battery. How far apart must the parallel plates be to have an electric field of $1.0 \mu \mathrm{V} / \mathrm{m}$ between the plates?

Short Answer

Expert verified
Answer: The distance between the parallel plates must be 1.5 x 10^6 meters.

Step by step solution

01

Write down the formula for electric field in a parallel plate capacitor

The electric field in a parallel plate capacitor can be calculated using the following formula: \(E = \frac{V}{d}\) where \(E\) is the electric field, \(V\) is the voltage, and \(d\) is the distance between the plates.
02

Plug in the given values

We are given the electric field \(E = 1.0 \mu \mathrm{V} / \mathrm{m}\) and the voltage \(V = 1.5 \, \mathrm{V}\). We can plug these values into the formula: \(1.0 \times 10^{-6} \, \mathrm{V/m} = \frac{1.5 \, \mathrm{V}}{d}\)
03

Solve for the distance \(d\)

Now we need to solve for \(d\): \(d = \frac{1.5 \, \mathrm{V}}{1.0 \times 10^{-6} \, \mathrm{V/m}}\)
04

Calculate the distance

Multiply both the numerator and denominator: \(d = \frac{1.5}{1.0 \times 10^{-6}} \, \mathrm{m}\) \(d = 1.5 \times 10^{6} \, \mathrm{m}\)
05

Write the final answer

The distance between the parallel plates must be \(1.5\times 10^{6}\) meters to have an electric field of \(1.0 \mu \mathrm{V/m}\).

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