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Chapter 18: Problem 105

A 1.5 -horsepower motor operates on \(120 \mathrm{V}\). Ignoring \(l^{2} R\) losses, how much current does it draw?

Short Answer

Expert verified
Answer: The current drawn by the motor is 9.325 amperes (A).

Step by step solution

01

Convert the power from horsepower to watts

To convert the power of the motor from 1.5 horsepower to watts, we can use the conversion factor: 1 horsepower = 746 watts. So, the power in watts is: Power (in watts) = 1.5 * 746 Power (in watts) = 1119 W
02

Use the formula for electrical power: Power = Voltage × Current

We can now use the formula for electrical power to solve for the current drawn by the motor: Power = Voltage × Current Rearrange the equation to solve for the current: Current = Power / Voltage
03

Substitute the given values and calculate the current

We have the power in watts (1119 W) and the voltage (120 V). Substitute these values into the equation to find the current: Current = 1119 W / 120 V Current = 9.325 A
04

Include units in the final result

The final step is to include the units in our result. The current drawn by the motor is 9.325 amperes (A).

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Most popular questions from this chapter

A solar cell provides an emf of \(0.45 \mathrm{V}\). (a) If the cell supplies a constant current of \(18.0 \mathrm{mA}\) for \(9.0 \mathrm{h},\) how much electric energy does it supply? (b) What is the power-the rate at which it supplies electric energy?
A potential difference is applied between the electrodes in a gas discharge tube. In 1.0 s, \(3.8 \times 10^{16}\) electrons and \(1.2 \times 10^{16}\) singly charged positive ions move in opposite directions through a surface perpendicular to the length of the tube. What is the current in the tube?
A voltmeter has a switch that enables voltages to be measured with a maximum of \(25.0 \mathrm{V}\) or \(10.0 \mathrm{V}\). For a range of voltages to $25.0 \mathrm{V},\( the switch connects a resistor of magnitude \)9850 \Omega$ in series with the galvanometer; for a range of voltages to \(10.0 \mathrm{V}\), the switch connects a resistor of magnitude \(3850 \Omega\) in series with the galvanometer. Find the coil resistance of the galvanometer and the galvanometer current that causes a full-scale deflection. [Hint: There are two unknowns, so you will need to solve two equations simultaneously.]
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Refer to Problem \(34 .\) With the copper wire connected to an ideal battery, the current increases greatly when the wire is immersed in liquid nitrogen. Ignoring changes in the wire's dimensions, state whether each of the following quantities increases, decreases, or stays the same as the wire is cooled: the electric field in the wire, the resistivity, and the drift speed. Explain your answers.
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