A copper wire of cross-sectional area \(1.00 \mathrm{mm}^{2}\) has a current of 2.0 A flowing along its length. What is the drift speed of the conduction electrons? Assume \(1.3 \mathrm{con}-\) duction electrons per copper atom. The mass density of copper is \(9.0 \mathrm{g} / \mathrm{cm}^{3}\) and its atomic mass is \(64 \mathrm{g} / \mathrm{mol}\).

Question: Calculate the drift speed of conduction electrons in a copper wire with a cross-sectional area of 1.00 mm², given a current of 2.0 A, 1.3 electrons per copper atom, a mass density of 9.0 g/cm³, and an atomic mass of 64 g/mol. Answer: To find the drift speed, follow the steps below: 1. Identify the drift speed formula: I = nAv_e, where I is the current, n is the charge density, A is the cross-sectional area, and v is the drift speed. 2. Calculate the number of electrons per unit volume (n) using the mass density and atomic mass, Avogadro's number, and the number of electrons per copper atom: n = (6.022 × 10²³ atoms/mol × 1.3 electons/atom)/(64 g/mol / 9.0 g/cm³). 3. Plug in the calculated n value, the given cross-sectional area, current, and the charge of an electron (1.6 × 10⁻¹⁹ C) into the drift speed formula: v_d = (2.0 A) / (n × 1.00 mm² × 1.6 × 10⁻¹⁹ C). After calculating the values, you will obtain the drift speed of conduction electrons in the copper wire.