A \(12-\Omega\) resistor has a potential difference of \(16 \mathrm{V}\) across it. What current flows through the resistor?

Short Answer

Expert verified
Answer: The current flowing through the resistor is \(\frac{4}{3}\,\mathrm{A}\) or approximately \(1.33\,\mathrm{A}\).

Step by step solution

01

Write down the given values

The problem gives us the resistance (R) which is \(12\,\Omega\) and the potential difference (V) which is \(16\,V\).
02

Write down the formula for Ohm's Law

Ohm's Law is \(V = IR\). We need to solve for the current (I) in this case.
03

Rearrange the formula to solve for I

Since we are trying to find the current (I), we need to rearrange Ohm's Law to isolate I on one side. To do this, divide both sides by R. The rearranged formula is \(I = \frac{V}{R}\).
04

Plug in the given values and calculate the current

Now we can substitute the given values of V and R into the formula. \(I = \frac{16\mathrm{V}}{12\Omega} = \frac{4}{3}\,\mathrm{A}\) The current flowing through the resistor is \(\frac{4}{3}\,\mathrm{A}\) or approximately \(1.33\,\mathrm{A}\).

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