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Chapter 18: Problem 9

What is the energy stored in a small battery if it can move \(675 \mathrm{C}\) through a potential difference of \(1.20 \mathrm{V} ?\)

Short Answer

Expert verified
Answer: The energy stored in the small battery is 810 Joules.

Step by step solution

01

Write down the formula for electric potential energy

The formula for electric potential energy (E) is given by: E = Q * V where Q is the charge in Coulombs (C) and V is the potential difference in Volts (V).
02

Substitute the given values into the formula

Now, we have the charge Q = 675 C and potential difference V = 1.20 V. We substitute these values into the formula: E = 675 * 1.20
03

Compute the energy stored in the battery

Multiplying the charge and potential difference, we get: E = 810 J The energy stored in the small battery is 810 Joules.

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Most popular questions from this chapter

A gold wire of 0.50 mm diameter has \(5.90 \times 10^{28} \mathrm{con}\) duction electrons/m". If the drift speed is \(6.5 \mu \mathrm{m} / \mathrm{s}\), what is the current in the wire?
A \(1.5-\mathrm{V}\) flashlight battery can maintain a current of $0.30 \mathrm{A}\( for \)4.0 \mathrm{h}$ before it is exhausted. How much chemical energy is converted to electrical energy in this process? (Assume zero internal resistance of the battery.)
A portable CD player does not have a power rating listed, but it has a label stating that it draws a maximum current of \(250.0 \mathrm{mA}\). The player uses three \(1.50-\mathrm{V}\) batteries connected in series. What is the maximum power consumed?
A Vespa scooter and a Toyota automobile might both use a \(12-\mathrm{V}\) battery, but the two batteries are of different sizes and can pump different amounts of charge. Suppose the scooter battery can pump 4.0 kC of charge and the automobile battery can pump \(30.0 \mathrm{kC}\) of charge. How much energy can each battery deliver, assuming the batteries are ideal?
A current of \(10.0 \mathrm{A}\) is carried by a copper wire of diameter $1.00 \mathrm{mm} .\( If the density of the conduction electrons is \)8.47 \times 10^{28} \mathrm{m}^{-3},$ how long does it take for a conduction electron to move \(1.00 \mathrm{m}\) along the wire?
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