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Chapter 19: Problem 3

Two identical bar magnets lic next to one another on a table. Sketch the magnetic ficld lines if the north poles are at the same end.

Short Answer

Expert verified
Short Answer: When two identical bar magnets are placed with their north poles at the same end, the magnetic field lines between the north poles repel each other, forming an arc. Between the south poles, the field lines attract each other, forming straight lines. The field lines curve around the sides of the magnets, connecting the north pole of one magnet to the south pole of the other magnet in the gap between the two. The magnetic field lines never intersect and are closer together near the poles.

Step by step solution

01

Understanding the magnetic field of a single bar magnet

A bar magnet has two poles, north and south. The magnetic field lines flow from the north pole to the south pole outside the magnet and from the south pole to the north pole inside the magnet. The field lines are closer together at the poles, where the magnetic field is stronger, and spread out as they go away from the poles.
02

Placing two identical bar magnets on a table

Place two identical bar magnets on a table, with the north pole of both magnets at the same end and the south poles at the opposite ends. The two magnets should be parallel to each other with a small gap between them.
03

Sketching the magnetic field lines for the north poles

Since both north poles are at the same end, the magnetic field lines would repel each other between the north poles. Draw the field lines curving away from each other, forming an arc between the north poles. The magnetic field lines would not cross or intersect each other.
04

Sketching the magnetic field lines for the south poles

At the opposite end with the south poles, the magnetic field lines will flow directly between the two south poles, as they attract each other. Draw the field lines as straight lines connecting both south poles.
05

Sketching the magnetic field lines around the bar magnets

Starting from the north pole of each magnet, draw the field lines curving around the sides of the magnets and connecting to the south poles of each magnet. Remember that the magnetic field lines never cross each other as they travel from one pole to another.
06

Sketching the magnetic field lines in the middle of the bar magnets

In the gap between the two bar magnets, draw the magnetic field lines connecting the north pole of one magnet to the south pole of the other magnet.
07

Completing the sketch

Review the sketch and verify if the magnetic field lines are consistent with the behavior of bar magnets. The field lines must not intersect, must be closer together near the poles, and must flow from the north pole to the south pole, both inside and outside the magnet. If the sketch follows these principles, the task is complete.

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Most popular questions from this chapter

A straight wire segment of length \(25 \mathrm{cm}\) carries a current of $33.0 \mathrm{A}$ and is immersed in a uniform external magnetic field. The magnetic force on the wire segment has magnitude \(4.12 \mathrm{N} .\) (a) What is the minimum possible magnitude of the magnetic field? (b) Explain why the given information enables you to calculate only the minimum possible field strength.
A solenoid has 4850 turns per meter and radius \(3.3 \mathrm{cm}\) The magnetic field inside has magnitude 0.24 T. What is the current in the solenoid?
A positron \((q=+e)\) moves at \(5.0 \times 10^{7} \mathrm{m} / \mathrm{s}\) in a magnetic field of magnitude 0.47 T. The magnetic force on the positron has magnitude \(2.3 \times 10^{-12} \mathrm{N} .\) (a) What is the component of the positron's velocity perpendicular to the magnetic field? (b) What is the component of the positron's velocity parallel to the magnetic field? (c) What is the angle between the velocity and the field?
In a simple model, the electron in a hydrogen atom orbits the proton at a radius of \(53 \mathrm{pm}\) and at a constant speed of $2.2 \times 10^{6} \mathrm{m} / \mathrm{s} .$ The orbital motion of the electron gives it an orbital magnetic dipole moment. (a) What is the current \(I\) in this current loop? [Hint: How long does it take the electron to make one revolution?] (b) What is the orbital dipole moment IA? (c) Compare the orbital dipole moment with the intrinsic magnetic dipole moment of the electron $\left(9.3 \times 10^{-24} \mathrm{A} \cdot \mathrm{m}^{2}\right)$
A charged particle is accelerated from rest through a potential difference \(\Delta V\). The particle then passes straight through a velocity selector (field magnitudes \(E\) and \(B\) ). Derive an expression for the charge-to-mass ratio \((q / m)\) of the particle in terms of \(\Delta V, E,\) and \(B\)
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