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Chapter 19: Problem 5

Two identical bar magnets lic onatable along a straight line with their north poles facing each other. Sketch the magnetic field lines.

Short Answer

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Short Answer: The magnetic field lines for two identical bar magnets with their North Poles facing each other will curve outward and repel each other between the magnets, due to the repulsion of like poles. On the outside of the magnets, the field lines will join together, forming a continuous loop to represent the overall magnetic field.

Step by step solution

01

Understanding Magnetic Field Lines

Magnetic field lines represent the magnetic field created by magnets. They show the direction of the magnetic force acting on a magnetic object placed in the field and are always continuous closed loops. They start at the North Pole and end at the South Pole of a magnet. The closer the field lines are, the stronger the magnetic field.
02

Drawing the Magnetic Field Lines for a Single Bar Magnet

To understand the interaction between two bar magnets, first, let's consider the magnetic field lines of a single bar magnet. Starting from its North Pole, the magnetic field lines curve away from the magnet, continue in a loop, and return to the magnet at its South Pole. The field lines maintain a continuous loop.
03

Drawing the Magnetic Field Lines for Two Identical Bar Magnets with North Poles Facing Each Other

Now, place the two bar magnets on a table along a straight line with their North Poles facing each other. Since like poles repel each other, the magnetic field lines in the region between the two North Poles will push against each other, causing them to curve away from the line connecting the two North Poles. On the other hand, in the regions outside the magnets, the magnetic field lines will join with each other and act like a single longer magnet. To summarize, the magnetic field lines near the North Poles will curve outward and repel each other, while on the outside of the magnets, the field lines will combine and appear like a single continuous loop.
04

Final Sketch: Magnetic Field Lines for Two Identical Bar Magnets with North Poles Facing Each Other

Draw the two bar magnets on a table, with their North Poles facing each other along a straight line. Sketch the magnetic field lines between the magnets, curving away from the line connecting the two North Poles, reflecting the repulsion between the like poles. Outside the magnets, show the field lines joining together, forming a continuous loop to represent the overall magnetic field.

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Most popular questions from this chapter

Electrons in a television's CRT are accelerated from rest by an electric field through a potential difference of \(2.5 \mathrm{kV} .\) In contrast to an oscilloscope, where the electron beam is deflected by an electric ficld, the beam is deflected by a magnetic field. (a) What is the specd of the electrons? (b) The beam is deflected by a perpendicular magnetic field of magnitude $0.80 \mathrm{T}$. What is the magnitude of the acceleration of the electrons while in the field? (c) What is the speed of the electrons after they travel 4.0 mm through the magnetic field? (d) What strength electric field would give the electrons the same magnitude acceleration as in (b)? (c) Why do we have to use an clectric ficld in the first place to get the electrons up to speed? Why not use the large acceleration due to a magnetic field for that purpose?
An electron moves with speed \(2.0 \times 10^{5} \mathrm{m} / \mathrm{s}\) in a uniform magnetic field of \(1.4 \mathrm{T},\) pointing south. At one instant, the electron experiences an upward magnetic force of $1.6 \times 10^{-14} \mathrm{N} .$ In what direction is the electron moving at that instant? Be specific: give the angle(s) with respect to $\mathrm{N}, \mathrm{S}, \mathrm{E}, \mathrm{W},$ up, down. (If there is more than one possible answer, find all the possibilitics.)
A long straight wire carries a current of 3.2 \(A\) in the positive \(x\)-direction. An electron, traveling at \(6.8 × 10 6\) m/s in the positive \(x\) -direction, is 4.6 cm from the wire. What force acts on the electron?
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Prove that the time for one revolution of a charged particle moving perpendicular to a uniform magnetic field is independent of its speed. (This is the principle on which the cyclotron operates.) In doing so, write an expression that gives the period \(T\) (the time for one revolution) in terms of the mass of the particle, the charge of the particle, and the magnetic field strength.
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