A solenoid of length \(0.256 \mathrm{m}\) and radius \(2.0 \mathrm{cm}\) has 244 turns of wire. What is the magnitude of the magnetic field well inside the solenoid when there is a current of \(4.5 \mathrm{A}\) in the wire?

Short Answer

Expert verified
Answer: The magnitude of the magnetic field inside the solenoid is approximately 5.39 x 10^{-3} T.

Step by step solution

01

Identify the given values

We are given the following values: - Length of the solenoid \((L) = 0.256 \,\text{m}\) - Radius of the solenoid \((R) = 2.0 \,\text{cm} = 0.020 \,\text{m}\) - Number of turns of wire \((n) = 244\) - Current in the wire \((I) = 4.5 \,\text{A}\)
02

Calculate the number of turns per unit length

To find the magnetic field inside the solenoid, we first need to find the number of turns per unit length \((n')\). This value is found by dividing the number of turns by the length of the solenoid: \(n' = \frac{n}{L}\) Plugging in the given values, we find: \(n' = \frac{244}{0.256 \,\text{m}} \approx 953.13 \, \text{turns/m}\)
03

Apply the formula for the magnetic field inside a solenoid

The formula for the magnetic field inside a solenoid is given by: \(B = \mu_0 n' I\) Where \(B\) is the magnetic field, \(\mu_0\) is the magnetic permeability of free space, and \(I\) is the current in the wire. The magnetic permeability of free space is a constant equal to \(\mu_0 = 4\pi \times 10^{-7} \, \text{Tm/A}\). Now, we plug in the values: \(B = (4\pi \times 10^{-7} \, \text{Tm/A})(953.13 \, \text{turns/m})(4.5 \,\text{A})\)
04

Calculate the magnetic field

Performing the multiplication, we obtain the magnitude of the magnetic field inside the solenoid: \(B \approx (4\pi \times 10^{-7} \, \text{Tm/A})(953.13 \, \text{turns/m})(4.5 \,\text{A})\) \(B \approx 5.39 \times 10^{-3} \, \text{T}\) Thus, the magnitude of the magnetic field well inside the solenoid when there is a current of \(4.5 \,\text{A}\) in the wire is approximately \(5.39 \times 10^{-3} \, \text{T}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two identical bar magnets lic next to one another on a table. Sketch the magnetic ficld lines if the north poles are at the same end.
A \(20.0 \mathrm{cm} \times 30.0 \mathrm{cm}\) rectangular loop of wire carries \(1.0 \mathrm{A}\) of current clockwise around the loop. (a) Find the magnetic force on each side of the loop if the magnetic ficld is 2.5 T out of the page. (b) What is the net magnetic force on the loop?
Four long parallel wires pass through the corners of a square with side $0.10 \mathrm{m}\(. All four wires carry the same magnitude of current \)I=10.0 \mathrm{A}\( in the directions indicated. Find the magnetic field at point \)R,$ the midpoint of the left side of the square.
A straight wire is aligned north-south in a region where Earth's magnetic field \(\overrightarrow{\mathbf{B}}\) is directed \(58.0^{\circ}\) above the horizontal, with the horizontal component directed due north. The wire carries a current of \(8.00 \mathrm{A}\) toward the south. The magnetic force on the wire per unit length of wire has magnitude $2.80 \times 10^{-3} \mathrm{N} / \mathrm{m} .$ (a) What is the direction of the magnetic force on the wire? (b) What is the magnitude of \(\mathbf{B} ?\)
A square loop of wire of side \(3.0 \mathrm{cm}\) carries \(3.0 \mathrm{A}\) of current. A uniform magnetic field of magnitude \(0.67 \mathrm{T}\) makes an angle of \(37^{\circ}\) with the plane of the loop. (a) What is the magnitude of the torque on the loop? (b) What is the net magnetic force on the loop?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free