Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 16

To pass a physical fitness test, Massimo must run \(1000 \mathrm{m}\) at an average rate of \(4.0 \mathrm{m} / \mathrm{s} .\) He runs the first $900 \mathrm{m}\( in \)250 \mathrm{s} .$ Is it possible for Massimo to pass the test? If so, how fast must he run the last 100 m to pass the test? Explain.

Short Answer

Expert verified
Answer: No, Massimo cannot pass the fitness test because he has already spent all of the required 250 seconds running the first 900 meters, leaving him no time to cover the remaining 100 meters.

Step by step solution

01

Calculate Massimo's average speed so far

First, we need to find Massimo's average speed for the first 900 meters he has run. We will use the following formula: average speed = distance (m) / time (s). Massimo has covered 900 meters in 250 seconds. So his average speed for the first 900 meters is: average speed = \(\frac{900}{250}\) = \(3.6 \frac{\mathrm{m}}{\mathrm{s}}\).
02

Calculate the required total time

Massimo must maintain an average speed of 4.0 m/s for the entire 1000-meter run to pass the test. To find the total time required to run 1000 meters at this speed, we can rearrange the formula for the average speed: time (s) = distance (m) / average speed. total time = \(\frac{1000}{4}\) = \(250 \mathrm{s}\).
03

Calculate the remaining time to run 100 meters

Since Massimo has already run the first 900 meters in 250 seconds, we need to calculate how much time he needs to spend running the last 100 meters to maintain the required average speed of 4.0 m/s. Subtract his time for the first 900 meters from the required total time to get the remaining time: remaining time = total time - time spent on 900 meters = 250 - 250 = 0 seconds.
04

Conclusion

Since Massimo has already spent all of the required 250 seconds running the first 900 meters, he has no time left to cover the remaining 100 meters. Therefore, it is not possible for him to pass the test by maintaining an average speed of 4.0 m/s for the entire 1000 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A runner, jogging along a straight line path, starts at a position $60 \mathrm{m}$ east of a milestone marker and heads west. After a short time interval he is \(20 \mathrm{m}\) west of the mile marker. Choose east to be the positive \(x\) -direction. (a) What is the runner's displacement from his starting point? (b) What is his displacement from the milestone? (c) The runner then turns around and heads east. If at a later time the runner is \(140 \mathrm{m}\) east of the milestone, what is his displacement from the starting point at this time? (d) What is the total distance traveled from the starting point if the runner stops at the final position listed in part (c)?
A cyclist travels \(10.0 \mathrm{km}\) east in a time of $11 \mathrm{min} 40 \mathrm{s}$ What is his average velocity in meters per second?
please assume the free-fall acceleration \(g=9.80 \mathrm{m} / \mathrm{s}^{2}\) unless a more precise value is given in the problem statement. Ignore air resistance. A 55 -kg lead ball is dropped from the leaning tower of Pisa. The tower is 55 m high. (a) How far does the ball fall in the first 3.0 s of flight? (b) What is the speed of the ball after it has traveled 2.5 m downward? (c) What is the speed of the ball 3.0 s after it is released? (d) If the ball is thrown vertically upward from the top of the tower with an initial speed of $4.80 \mathrm{m} / \mathrm{s}$, where will it be after 2.42 s?
Two cars, a Toyota Yaris and a Jeep, are traveling in the same direction, although the Yaris is \(186 \mathrm{m}\) behind the Jeep. The speed of the Yaris is \(24.4 \mathrm{m} / \mathrm{s}\) and the speed of the Jeep is $18.6 \mathrm{m} / \mathrm{s}$. How much time does it take for the Yaris to catch the Jeep? [Hint: What must be true about the displacement of the two cars when they meet?]
For the train of Example \(2.2,\) find the average velocity between 3: 14 P.M. when the train is at \(3 \mathrm{km}\) east of the origin and 3: 28 P.M. when it is \(10 \mathrm{km}\) east of the origin.
See all solutions

Recommended explanations on Physics Textbooks

Kinematics Physics

Read Explanation

Force

Read Explanation

Fields in Physics

Read Explanation

Solid State Physics

Read Explanation

Waves Physics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free