A portable heater is connected to a \(60-\mathrm{Hz}\) ac outlet. How many times per second is the instantancous power a maximum?

Short Answer

Expert verified
Answer: The instantaneous power in an AC circuit reaches its maximum value 120 times per second at a frequency of 60 Hz.

Step by step solution

01

Understand the relationship between power and frequency in an AC circuit

In an AC circuit, the instantaneous power is given by the formula \(P(t) = VI\cos(\phi)\cos(2\pi ft)\). Here, \(V\) is the instantaneous voltage, \(I\) is the instantaneous current, \(\phi\) is the phase angle between voltage and current, and \(f\) is the frequency. \(P(t)\) is a maximum when \(\cos(2\pi ft) = \pm 1\).
02

Calculate the number of times the power hits a maximum in a single cycle

Within one AC cycle, which occurs each \(\frac{1}{f}\) seconds, \(\cos(2\pi ft)\) will equal \(\pm 1\) twice. Since there are \(2\pi\) radians in a full cycle and \(\cos(x) = \pm 1\) where \(x=2n\pi\) (where n is an integer), we can deduce that the power would maximize twice at \(2n\pi = 2\pi\) and \(2n\pi = 4\pi\) within that cycle.
03

Multiply the number of maximum power instances in a single cycle by the frequency to find the final answer

As established in step 2, the power maximizes twice in a single cycle. Therefore, for a frequency of \(60 Hz\), the power will hit its maximum value \(60 * 2 = 120\) times per second.

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