The field coils used in an ac motor are designed to have a resistance of $0.45 \Omega\( and an impedance of \)35.0 \Omega$ What inductance is required if the frequency of the ac source is (a) \(60.0 \mathrm{Hz} ?\) and (b) $0.20 \mathrm{kHz} ?$

Short Answer

Expert verified
Answer: (a) 1.66 H (b) 0.055 H

Step by step solution

01

Calculate the inductive reactance at each frequency

First, we need to calculate the inductive reactance (\(X_L\)) for both frequencies using the formula: $$X_L = \sqrt{Z^2 - R^2}$$ For (a): $$X_{L1} = \sqrt{(35.0\,\Omega)^2 - (0.45\,\Omega)^2}$$ For (b): $$X_{L2} = \sqrt{(35.0\,\Omega)^2 - (0.45\,\Omega)^2}$$ Notice that the given impedance and resistance are the same for both frequencies, so our calculation for both \(X_{L1}\) and \(X_{L2}\) is the same.
02

Calculate the inductance for each frequency

Now that we have the inductive reactance at each frequency, we can use the formula that relates frequency, inductance, and inductive reactance: $$X_L = 2\pi f L$$ We will solve for \(L\) at each frequency: For (a): $$L_1 = \frac{X_{L1}}{2\pi f_1}$$ For (b): $$L_2 = \frac{X_{L2}}{2\pi f_2}$$
03

Plug in the values and compute the results

Now we will plug in the values for the inductive reactance and frequency, and compute the inductance for both cases: For (a): $$L_1 = \frac{\sqrt{(35.0\,\Omega)^2 - (0.45\,\Omega)^2}}{2\pi (60.0\,\mathrm{Hz})}$$ For (b): $$L_2 = \frac{\sqrt{(35.0\,\Omega)^2 - (0.45\,\Omega)^2}}{2\pi (0.20\,\mathrm{kHz})}$$ Solving for \(L_1\) and \(L_2\), we get the required inductance for each frequency: $$L_1 = 1.66 \,\mathrm{H}$$ $$L_2 = 0.055 \,\mathrm{H}$$

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