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Chapter 22: Problem 16

How long does it take sunlight to travel from the Sun to Earth?

Short Answer

Expert verified
Answer: Approximately 8.31 minutes.

Step by step solution

01

Convert the distance into the same unit as the speed

We need to convert the distance from the Sun to Earth to the same unit as the speed of light. Let's convert the distance into miles. Distance = 93,000,000 miles
02

Rearrange the speed formula to find time

The formula of speed is Speed = Distance/Time. We need to rearrange the formula to find time: Time = Distance / Speed
03

Substitute the distance and speed values into the formula

Now, we will substitute the distance and speed values into the formula to find the time: Time = (93,000,000 miles) / (186,282 miles/second)
04

Calculate the time

After substituting the values, we can now calculate the time it takes for sunlight to travel from the Sun to Earth: Time = (93,000,000 miles) / (186,282 miles/second) = 498.67 seconds
05

Convert the time into a more convenient unit

Since 498.67 seconds is not easy to understand, let's convert it into minutes: Time = 498.67 seconds / 60 seconds/minute = 8.31 minutes So, it takes approximately 8.31 minutes for sunlight to travel from the Sun to Earth.

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Most popular questions from this chapter

A 60.0 -m \(\mathrm{W}\) pulsed laser produces a pulse of EM radia tion with wavelength \(1060 \mathrm{nm}\) (in air) that lasts for 20.0 ps (picoseconds). (a) In what part of the EM spectrum is this pulse? (b) How long (in centimeters) is : single pulse in air? (c) How long is it in water \((n=1.33) \equiv\) (d) How many wavelengths fit in one pulse? (e) What is the total electromagnetic energy in one pulse?
The range of wavelengths allotted to the radio broadcast band is from about \(190 \mathrm{m}\) to \(550 \mathrm{m} .\) If each station needs exclusive use of a frequency band \(10 \mathrm{kHz}\) wide, how many stations can operate in the broadcast band?
What must be the relative speed between source and receiver if the wavelength of an EM wave as measured by the receiver is twice the wavelength as measured by the source? Are source and observer moving closer together or farther apart?
An electric dipole antenna used to transmit radio waves is oriented vertically.At a point due north of the transmitter, how should a magnetic dipole antenna be oriented to serve as a receiver?
The electric field of an EM wave is given by \(E_{z}=\) $E_{\mathrm{m}} \sin (k y-\omega t+\pi / 6), E_{x}=0,\( and \)E_{z}=0 .$ (a) In what direction is this wave traveling? (b) Write expressions for the components of the magnetic field of this wave.
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