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Chapter 23: Problem 40

A rose in a vase is placed \(0.250 \mathrm{m}\) in front of a plane mirror. Nagar looks into the mirror from \(2.00 \mathrm{m}\) in front of it. How far away from Nagar is the image of the rose?

Short Answer

Expert verified
Answer: The distance from Nagar to the image of the rose in the plane mirror is 2.25 meters.

Step by step solution

01

Identify given information

We have the following information: - The distance between the rose and the mirror is \(0.250 \mathrm{m}\). - Nagar is \(2.00 \mathrm{m}\) in front of the mirror.
02

Find the distance between the rose's image and the mirror

Since a plane mirror reflects the object at the same distance it is located from the mirror, the image of the rose is also \(0.250 \mathrm{m}\) behind the mirror.
03

Add the distance from Nagar to the distance from the image

Now, we can find the total distance between Nagar and the image of the rose by adding the distance between Nagar and the mirror (\(2.00 \mathrm{m}\)) to the distance between the image of the rose and the mirror (\(0.250 \mathrm{m}\)): \( distance = 2.00 \mathrm{m} + 0.250 \mathrm{m} \)
04

Calculate the total distance

We can now calculate the total distance: \( distance = 2.00 \mathrm{m} + 0.250 \mathrm{m} = 2.25 \mathrm{m} \) So, the distance from Nagar to the image of the rose is \(2.25 \mathrm{m}\).

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The focal length of a thin lens is \(-20.0 \mathrm{cm} .\) A screen is placed \(160 \mathrm{cm}\) from the lens. What is the \(y\) -coordinate of the point where the light ray shown hits the screen? The incident ray is parallel to the central axis and is \(1.0 \mathrm{cm}\) from that axis.
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