Sketch a ray diagram to show that when an object is placed at twice the focal length from a converging lens, the image formed is inverted, real, and the same size as the object.

Short Answer

Expert verified
Question: Sketch a ray diagram for a converging lens with an object placed at a distance equal to twice the focal length. Describe the properties of the image formed. Answer: The image formed by the converging lens is real, inverted, and has the same size as the object. This is illustrated in the ray diagram, where the rays parallel to the optic axis and passing through the center of the lens intersect at the same place. The object is placed at a distance equal to twice the focal length, making the image formed at the same distance on the opposite side of the lens.

Step by step solution

01

Draw the optic axis, lens, and object

Start by drawing a straight horizontal line, which represents the optic axis. Then draw a converging lens at the center of the axis. Place an object (arrow representing the object is fine) on the optic axis at a distance equal to twice the focal length.
02

Draw the focal points and locate the object

Draw two points on the optic axis on either side of the lens to represent the focal points (F1 and F2). As we mentioned earlier, the object should be placed at a distance equal to twice the focal length, which means the object is located between F1 and double the distance from the lens to F1.
03

Draw a ray parallel to the optic axis from the top of the object

Draw a straight line (ray) from the top of the object parallel to the optic axis. This ray will pass through the lens and refract (bend) through the focal point (F2) on the other side.
04

Draw a ray passing through the center of the lens from the top of the object

Draw another ray from the top of the object through the exact center of the lens. This ray will not refract (bend) and will continue in a straight path.
05

Find the intersection of the rays

The image will be formed where the two rays (from Step 3 and Step 4) intersect on the opposite side of the lens. Draw an arrow from the intersection point down to the optic axis. This will represent the image.
06

Analyze the ray diagram

Notice that the image is formed on the opposite side of the object, making it real. Also, the image is inverted, as the arrow is pointing downward. Since the object was placed at twice the focal length, the image will be formed at the same distance (but on the other side of the lens), and the size of the image will be equal to the size of the object. This verifies the statements in the exercise.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A scuba diver in a lake aims her underwater spotlight at the lake surface. (a) If the beam makes a \(75^{\circ}\) angle of incidence with respect to a normal to the water surface, is it reflected, transmitted, or both? Find the angles of the reflected and transmitted beams (if they exist). (b) Repeat for a \(25^{\circ}\) angle of incidence.
The right-side decides to do an experiment to determine the focal length of this mirror. He holds a plane mirror next to the rearview mirror and views an object that is \(163 \mathrm{cm}\) away from each mirror. The object appears \(3.20 \mathrm{cm}\) wide in the plane mirror, but only \(1.80 \mathrm{cm}\) wide in the rearview mirror. What is the focal length of the rearview mirror? mirror of Mike's car says that objects in the mirror are closer than they appear. Mike
Sketch the wavefronts and rays for the light emitted by an isotropic point source (isotropic = same in all directions). Use Huygens's principle to illustrate the propagation of one of the wavefronts.
An object that is \(6.00 \mathrm{cm}\) tall is placed \(40.0 \mathrm{cm}\) in front of a diverging lens. The magnitude of the focal length of the lens is \(20.0 \mathrm{cm} .\) Find the image position and size. Is the image real or virtual? Upright or inverted?
In a subway station, a convex mirror allows the attendant to view activity on the platform. A woman \(1.64 \mathrm{m}\) tall is standing \(4.5 \mathrm{m}\) from the mirror. The image formed of the woman is \(0.500 \mathrm{m}\) tall. (a) What is the radius of curvature of the mirror? (b) The mirror is \(0.500 \mathrm{m}\) in diameter. If the woman's shoes appear at the bottom of the mirror, does her head appear at the top-in other words, does the image of the woman fill the mirror from top to bottom? Explain.
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free