How much energy must be supplied to a hydrogen atom to cause a transition from the ground state to the \(n=4\) state?

Short Answer

Expert verified
Answer: The energy required for the transition is 12.75 eV.

Step by step solution

01

Energy level formula for hydrogen atom

The formula to calculate the energy levels of the hydrogen atom is: \(E_n = -\frac{13.6 eV}{n^2}\), where \(E_n\) is the energy of the nth energy level and n is the principal quantum number.
02

Calculate the energy of the ground state (n=1)

Using the energy level formula, we can calculate the energy of the ground state (n=1): \(E_1 = -\frac{13.6 eV}{1^2} = -13.6 eV\)
03

Calculate the energy of the n=4 state

Now, we can calculate the energy of the n=4 state using the same formula: \(E_4 = -\frac{13.6 eV}{4^2} = -\frac{13.6 eV}{16} = -0.85 eV\)
04

Find the energy difference between the two states

To find the energy required for the transition, we need to calculate the energy difference between the two states: \(\Delta E = E_4 - E_1 = (-0.85 eV) - (-13.6 eV) = 12.75 eV\)
05

Final answer

The energy that must be supplied to cause a transition from the ground state to the n=4 state in a hydrogen atom is 12.75 eV.

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