Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 27: Problem 4

The photoelectric threshold frequency of silver is $1.04 \times 10^{15} \mathrm{Hz} .$ What is the minimum energy required to remove an electron from silver?

Short Answer

Expert verified
Answer: The minimum energy required to remove an electron from silver is \(6.89104 \times 10^{-19} \mathrm{J}\).

Step by step solution

01

Identify the given values and constants

We are given the threshold frequency of silver, \(\nu = 1.04 \times 10^{15} \mathrm{Hz}\). Planck's constant, \(h = 6.626 \times 10^{-34} \mathrm{Js}\)
02

Apply the photon energy formula

To find the minimum energy required to remove an electron from silver, we use the formula \(E = h \nu\).
03

Calculate the minimum energy

Now, substitute the given values of \(h\) and \(\nu\) into the formula: \(E = (6.626 \times 10^{-34} \mathrm{Js}) (1.04 \times 10^{15} \mathrm{Hz})\) \(E = 6.89104 \times 10^{-19} \mathrm{J}\)
04

Write the final answer

The minimum energy required to remove an electron from silver is \(6.89104 \times 10^{-19} \mathrm{J}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A photon of energy \(240.0 \mathrm{keV}\) is scattered by a free electron. If the recoil electron has a kinetic energy of \(190.0 \mathrm{keV},\) what is the wavelength of the scattered photon?
What is the minimum potential difference applied to an x-ray tube if \(x\) -rays of wavelength \(0.250 \mathrm{nm}\) are produced?
X-rays of wavelength \(10.0 \mathrm{pm}\) are incident on a target. Find the wavelengths of the \(x\) -rays scattered at (a) \(45.0^{\circ}\) and (b) \(90.0^{\circ} .\) (tutorial: Compton scattering)
An incident photon of wavelength \(0.0100 \mathrm{nm}\) is Compton scattered; the scattered photon has a wavelength of \(0.0124 \mathrm{nm} .\) What is the change in kinetic energy of the electron that scattered the photon?
In gamma-ray astronomy, the existence of positrons \(\left(\mathrm{e}^{+}\right)\) can be inferred by a characteristic gamma ray that is emitted when a positron and an electron (e \(^{-}\) ) annihilate. For simplicity, assume that the electron and positron are at rest with respect to an Earth observer when they annihilate and that nothing else is in the vicinity. (a) Consider the reactions $\mathrm{e}^{-}+\mathrm{e}^{+} \rightarrow \gamma$, where the annihilation of the two particles at rest produces one photon, and \(\mathrm{e}^{-}+\mathrm{e}^{+} \rightarrow 2 \gamma,\) where the annihilation produces two photons. Explain why the first reaction does not occur, but the second does. (b) Suppose the reaction \(\mathrm{e}^{-}+\mathrm{e}^{+} \rightarrow 2 \gamma\) occurs and one of the photons travels toward Earth. What is the energy of the photon?
See all solutions

Recommended explanations on Physics Textbooks

Wave Optics

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Electrostatics

Read Explanation

Particle Model of Matter

Read Explanation

Torque and Rotational Motion

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free