The particle in a box model is often used to make rough estimates of energy level spacings. For a metal wire \(10 \mathrm{cm}\) long, treat a conduction electron as a particle confined to a one-dimensional box of length \(10 \mathrm{cm} .\) (a) Sketch the wave function \(\psi\) as a function of position for the electron in this box for the ground state and each of the first three excited states. (b) Estimate the spacing between energy levels of the conduction electrons by finding the energy spacing between the ground state and the first excited state.

Short Answer

Expert verified
Question: Sketch the wave function for the ground state and the first three excited states for a conduction electron confined to a metal wire of length 10cm. Also, estimate the energy level spacing between the ground state and the first excited state. Answer: The wave function can be sketched for the ground state and the three excited states using the formula \(\psi _n(x) = \sqrt{\frac{2}{L}}\sin{\frac{n \pi x}{L}}\). The energy level spacing between the ground state and the first excited state can be calculated using the formula \(\Delta E_{1 \to 2} = \frac{3 \pi ^2 \hbar ^2}{2m_e L^2}\), which gives a value of approximately \(1.964 \times 10^{-9}\, \mathrm{eV}\).

Step by step solution

01

(a) Sketch the wave functions for different states

For a one-dimensional box from \(0\) to \(L\), the wave function for the electron can be expressed as: \(\psi _n(x) = \sqrt{\frac{2}{L}}\sin{\frac{n \pi x}{L}}\) where \(n\) is the principal quantum number (\(n = 1, 2, 3, ...\)) and \(L\) is the length of the box. For the ground state, \(n = 1\): \(\psi _1(x) = \sqrt{\frac{2}{10}}\sin{\frac{1 \pi x}{10}}\) For the first excited state, \(n = 2\): \(\psi _2(x) = \sqrt{\frac{2}{10}}\sin{\frac{2 \pi x}{10}}\) For the second excited state, \(n = 3\): \(\psi _3(x) = \sqrt{\frac{2}{10}}\sin{\frac{3 \pi x}{10}}\) For the third excited state, \(n = 4\): \(\psi _4(x) = \sqrt{\frac{2}{10}}\sin{\frac{4 \pi x}{10}}\) Based on these expressions, the student can sketch the wave function \(\psi\) as a function of position for the ground state and the first three excited states.
02

(b) Estimate the energy level spacing

To estimate the energy level spacing, we need to find the energy levels. The energy of a particle in a one-dimensional box can be expressed as: \(E_n = \frac{n^2 \pi ^2 \hbar ^2}{2m_e L^2}\) where \(n\) is the principal quantum number, \(\hbar\) is the reduced Planck constant, \(m_e\) is the mass of the electron, and \(L\) is the length of the box. The spacing between the ground state (\(n=1\)) and the first excited state (\(n=2\)) can be calculated as: \(\Delta E_{1 \to 2} = E_2 - E_1 = \frac{2^2 \pi ^2 \hbar ^2}{2m_e L^2} - \frac{1^2 \pi ^2 \hbar ^2}{2m_e L^2}\) This simplifies to: \(\Delta E_{1 \to 2} = \frac{3 \pi ^2 \hbar ^2}{2m_e L^2}\) Now, we can substitute the values of the constants and the length of the box: \(\Delta E_{1 \to 2} = \frac{3 \pi ^2 (6.582 \times 10^{-16} \mathrm{eV \cdot s})^2}{2(9.109 \times 10^{-31} \mathrm{kg})(10 \times 10^{-2} \mathrm{m})^2}\) \(\Delta E_{1 \to 2} = 1.964 \times 10^{-9}\, \mathrm{eV}\) So, the spacing between the energy levels of the conduction electrons is approximately \(1.964 \times 10^{-9}\, \mathrm{eV}\).

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