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Chapter 29: Problem 4

Write the symbol (in the form \(_{Z}^{A} \mathrm{X}\) ) for the nuclide with 38 protons and 50 neutrons and identify the element.

Short Answer

Expert verified
Answer: The nuclide symbol for an atom with 38 protons and 50 neutrons is \(_{38}^{88}\mathrm{Sr}\), and it represents the element Strontium.

Step by step solution

01

Determine the element with the atomic number of 38

Referring to the periodic table, find the element with 38 protons. In this case, it is Strontium (Sr).
02

Calculate the mass number

Calculate the mass number (A) by adding the number of protons and neutrons together: A = number of protons + number of neutrons = 38 + 50 = 88
03

Write the nuclide symbol

Now that we have found the element, and calculated the mass number, we can write the nuclide symbol as follows: \(_{38}^{88}\mathrm{Sr}\) So, the symbol for the nuclide with 38 protons and 50 neutrons is \(_{38}^{88}\mathrm{Sr}\), and the element is Strontium.

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Most popular questions from this chapter

An isotope of sodium, \({ }_{11}^{2} \mathrm{Na}\), decays by \(\beta^{+}\) emission. Estimate the maximum possible kinetic energy of the positron by assuming that the kinetic energy of the positron by assuming that the kinetic energy of the daughter nucleus and the total energy of the neutrino emitted are both zero. [Hint: Remember to keep track of the electron masses.
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