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Chapter 29: Problem 8

Write the symbol (in the form \(_{Z}^{A} \mathrm{X}\) ) for the nuclide that has 78 neutrons and 53 protons.

Short Answer

Expert verified
Answer: The nuclide symbol for this isotope is \(_{53}^{131} \mathrm{I}\).

Step by step solution

01

Find the element symbol

The element symbol can be found by matching the atomic number (Z) to its corresponding element in the periodic table. The problem states that there are 53 protons, so the atomic number is 53. Upon looking it up on the periodic table, the element with Z = 53 is Iodine (I).
02

Calculate the mass number

To find the mass number (A), add the number of protons (Z) and the number of neutrons. In this case, there are 53 protons and 78 neutrons. The mass number is then: A = 53 (protons) + 78 (neutrons) = 131
03

Write the nuclide symbol

Using the values found in steps 1 and 2, the nuclide symbol in the form \(_{Z}^{A} \mathrm{X}\) can be written as: \(_{53}^{131} \mathrm{I}\)

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Most popular questions from this chapter

Suppose that a radioactive sample contains equal numbers of two radioactive nuclides \(A\) and \(B\) at \(t=0 .\) A has a half-life of \(3.0 \mathrm{h},\) while \(\mathrm{B}\) has a half-life of \(12.0 \mathrm{h}\) Find the ratio of the decay rates or activities \(R_{\mathrm{A}} / R_{\mathrm{B}}\) at (a) \(t=0,\) (b) \(t=12.0 \mathrm{h},\) and \((\mathrm{c}) t=24.0 \mathrm{h}\).
Thorium-232 ( \(^{232}\) Th) decays via \(\alpha\) decay. Write out the reaction and identify the daughter nuclide.
A neutron star is a star that has collapsed into a collection of tightly packed neutrons. Thus, it is something like a giant nucleus; but since it is electrically neutral, there is no Coulomb repulsion to break it up. The force holding it together is gravity. Suppose the Sun were to collapse into a neutron star. What would its radius be? Assume that the density is about the same as for a nucleus. Express your answer in kilometers.
If meat is irradiated with 2000.0 Gy of \(\mathrm{x}\) -rays, most of the bacteria are killed and the shelf life of the meat is greatly increased. (a) How many 100.0 -keV photons must be absorbed by a \(0.30-\mathrm{kg}\) steak so that the absorbed dose is 2000.0 Gy? (b) Assuming steak has the same specific heat as water, what temperature increase is caused by a 2000.0 -Gy absorbed dose?
Show mathematically that $2^{-t / T_{12}}=\left(\frac{1}{2}\right)^{t / T_{12}}=e^{-t / \tau}\( if and only if \)T_{1 / 2}=\tau \ln 2 .$ [Hint: Take the natural logarithm of each side. \(]\)
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