Margaret walks to the store using the following path: 0.500 miles west, 0.200 miles north, 0.300 miles east. What is her total displacement? That is, what is the length and direction of the vector that points from her house directly to the store? Use vector components to find the answer.

Short Answer

Expert verified
Answer: Margaret's total displacement is approximately 0.2828 miles in the southwest direction at 45° from the west direction.

Step by step solution

01

Identify the vector components for each direction

Since Margaret walks west, north, and east, her path can be represented by three vectors: - Vector A: 0.500 miles west (negative x-direction) - Vector B: 0.200 miles north (positive y-direction) - Vector C: 0.300 miles east (positive x-direction)
02

Calculate the total displacement vector

Now we can find the total displacement vector by adding the vector components: Vector A: (-0.500, 0) Vector B: (0, 0.200) Vector C: (0.300, 0) Total Displacement Vector (D) = Vector A + Vector B + Vector C = (-0.500 + 0.300, 0 + 0.200) = (-0.200, 0.200)
03

Calculate the magnitude and direction of the displacement vector

To find the magnitude (length) of the displacement vector, we can use the Pythagorean theorem: Magnitude of D = sqrt((-0.200)^2 + (0.200)^2) = sqrt(0.04 + 0.04) = sqrt(0.08) = 0.2828 miles (approx.) To find the direction of the displacement vector, we can use the arctangent function (angle of the vector with the positive x-axis): Direction of D = arctan(0.200/-0.200) = arctan(-1) = -45° Since the angle is negative, this indicates that the direction is 45° below the negative x-axis (west). Thus, the direction of the displacement vector is 45° southwest.
04

Present the final answer

Margaret's total displacement is approximately 0.2828 miles in the southwest direction at 45° from the west direction.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A motor scooter rounds a curve on the highway at a constant speed of $20.0 \mathrm{m} / \mathrm{s} .$ The original direction of the scooter was due east; after rounding the curve the scooter is heading \(36^{\circ}\) north of east. The radius of curvature of the road at the location of the curve is $150 \mathrm{m}$ What is the average acceleration of the scooter as it rounds the curve?
A marble is rolled so that it is projected horizontally off the top landing of a staircase. The initial speed of the marble is $3.0 \mathrm{m} / \mathrm{s} .\( Each step is \)0.18 \mathrm{m}\( high and \)0.30 \mathrm{m}$ wide. Which step does the marble strike first?
You have been employed by the local circus to plan their human cannonball performance. For this act, a spring-loaded cannon will shoot a human projectile, the Great Flyinski, across the big top to a net below. The net is located \(5.0 \mathrm{m}\) lower than the muzzle of the cannon from which the Great Flyinski is launched. The cannon will shoot the Great Flyinski at an angle of \(35.0^{\circ}\) above the horizontal and at a speed of $18.0 \mathrm{m} / \mathrm{s} .$ The ringmaster has asked that you decide how far from the cannon to place the net so that the Great Flyinski will land in the net and not be splattered on the floor, which would greatly disturb the audience. What do you tell the ringmaster? ( Wheractive: projectile motion)
Jason is practicing his tennis stroke by hitting balls against a wall. The ball leaves his racquet at a height of \(60 \mathrm{cm}\) above the ground at an angle of \(80^{\circ}\) with respect to the vertical. (a) The speed of the ball as it leaves the racquet is \(20 \mathrm{m} / \mathrm{s}\) and it must travel a distance of \(10 \mathrm{m}\) before it reaches the wall. How far above the ground does the ball strike the wall? (b) Is the ball on its way up or down when it hits the wall?
A boy is attempting to swim directly across a river; he is able to swim at a speed of \(0.500 \mathrm{m} / \mathrm{s}\) relative to the water. The river is \(25.0 \mathrm{m}\) wide and the boy ends up at \(50.0 \mathrm{m}\) downstream from his starting point. (a) How fast is the current flowing in the river? (b) What is the speed of the boy relative to a friend standing on the riverbank?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free