You have been employed by the local circus to plan their human cannonball performance. For this act, a spring-loaded cannon will shoot a human projectile, the Great Flyinski, across the big top to a net below. The net is located \(5.0 \mathrm{m}\) lower than the muzzle of the cannon from which the Great Flyinski is launched. The cannon will shoot the Great Flyinski at an angle of \(35.0^{\circ}\) above the horizontal and at a speed of $18.0 \mathrm{m} / \mathrm{s} .$ The ringmaster has asked that you decide how far from the cannon to place the net so that the Great Flyinski will land in the net and not be splattered on the floor, which would greatly disturb the audience. What do you tell the ringmaster? ( Wheractive: projectile motion)

Short Answer

Expert verified
Answer: To find the distance the net should be placed, first calculate the horizontal and vertical components of the initial velocity. Then, find the time of flight using the vertical component and the height difference between the cannon and the net. Finally, use the time of flight and horizontal component to calculate the horizontal range where the net should be placed.

Step by step solution

01

Calculate horizontal and vertical components of velocity.

First, we need to find the horizontal (u_x) and vertical (u_y) components of the initial velocity of the Great Flyinski. Use the initial velocity (18 m/s) and the launch angle (35°) to find these components: u_x = u * cos(35°) u_y = u * sin(35°)
02

Find time of flight.

Next, we'll find the time for which the Great Flyinski is in the air (t_flight) by using the vertical component of velocity. We know the vertical displacement (Δy) which is `5.0 m` (the net is lower than the muzzle of the cannon) and we can use the formula for constant acceleration due to gravity (g = 9.8 m/s²) to find the time: Δy = u_y * t_flight - (1/2) * g * t_flight²
03

Calculate the horizontal range.

Now, we will use the time of flight (t_flight) and horizontal component of velocity (u_x) to find the horizontal distance (R) the net should be placed: R = u_x * t_flight
04

Solve for t_flight in Step 2.

Rearrange the equation obtained in Step 2 to isolate t_flight and then solve for it in terms of u_y, g, and Δy: t_flight = (u_y + sqrt(u_y² - 2 * g * Δy)) / g, or t_flight = (u_y - sqrt(u_y² - 2 * g * Δy)) / g
05

Find the value of R.

Substitute the values for u_x and t_flight obtained in the previous steps into the equation for R from Step 3: R = u_x * ((u_y + sqrt(u_y² - 2 * g * Δy)) / g) or R = u_x * ((u_y - sqrt(u_y² - 2 * g * Δy)) / g) Finally, we will calculate the approximate value for R. The ringmaster should place the net at this distance from the cannon to ensure that the Great Flyinski lands safely in the net.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Jason is practicing his tennis stroke by hitting balls against a wall. The ball leaves his racquet at a height of \(60 \mathrm{cm}\) above the ground at an angle of \(80^{\circ}\) with respect to the vertical. (a) The speed of the ball as it leaves the racquet is \(20 \mathrm{m} / \mathrm{s}\) and it must travel a distance of \(10 \mathrm{m}\) before it reaches the wall. How far above the ground does the ball strike the wall? (b) Is the ball on its way up or down when it hits the wall?
A motor scooter rounds a curve on the highway at a constant speed of $20.0 \mathrm{m} / \mathrm{s} .$ The original direction of the scooter was due east; after rounding the curve the scooter is heading \(36^{\circ}\) north of east. The radius of curvature of the road at the location of the curve is $150 \mathrm{m}$ What is the average acceleration of the scooter as it rounds the curve?
A locust jumps at an angle of \(55.0^{\circ}\) and lands \(0.800 \mathrm{m}\) from where it jumped. (a) What is the maximum height of the locust during its jump? Ignore air resistance. (b) If it jumps with the same initial speed at an angle of \(45.0^{\circ},\) would the maximum height be larger or smaller? (c) What about the range? (d) Calculate the maximum height and range for this angle.
A car is driving directly north on the freeway at a speed of $110 \mathrm{km} / \mathrm{h}$ and a truck is leaving the freeway driving \(85 \mathrm{km} / \mathrm{h}\) in a direction that is \(35^{\circ}\) west of north. What is the velocity of the truck relative to the car?
A helicopter is flying horizontally at \(8.0 \mathrm{m} / \mathrm{s}\) and an altitude of \(18 \mathrm{m}\) when a package of emergency medical supplies is ejected horizontally backward with a speed of \(12 \mathrm{m} / \mathrm{s}\) relative to the helicopter. Ignoring air resistance, what is the horizontal distance between the package and the helicopter when the package hits the ground?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free