A ballplayer standing at home plate hits a baseball that is caught by another player at the same height above the ground from which it was hit. The ball is hit with an initial velocity of \(22.0 \mathrm{m} / \mathrm{s}\) at an angle of \(60.0^{\circ}\) above the horizontal. (a) How high will the ball rise? (b) How much time will elapse from the time the ball leaves the bat until it reaches the fielder? (c) At what distance from home plate will the fielder be when he catches the ball?

Short Answer

Expert verified
(b) What is the time elapsed from the time the ball leaves the bat until it reaches the fielder? (c) What is the distance from home plate to the fielder when they catch the ball? Answer: Follow the step-by-step solution provided to calculate the values for (a) maximum height, (b) time elapsed, and (c) distance from home plate to the fielder when they catch the ball.

Step by step solution

01

Calculate the initial horizontal and vertical velocities

We have the initial velocity, \(v_0 = 22.0 \mathrm{m} / \mathrm{s}\), and launch angle, \(\theta = 60.0^{\circ}\). We will find the initial horizontal velocity, \(v_{0x}\), and vertical velocity, \(v_{0y}\), using the trigonometric functions: \(v_{0x} = v_0 \cos\theta\) \(v_{0y} = v_0 \sin\theta\)
02

Calculate the time of flight

Since the ball is caught at the same height it was hit, we know that the vertical displacement will be zero. Applying the kinematic equation for vertical motion: \(0 = v_{0y}t - \frac{1}{2}gt^2\) Solve this equation for the time, \(t\). Where \(g\) is the acceleration due to gravity, \(g = 9.81 \mathrm{m} / \mathrm{s^2}\).
03

Calculate the maximum height

To find the maximum height, we can use the following kinematic equation: \(h = v_{0y}t_1 - \frac{1}{2}gt_1^2\) Where \(h\) is the maximum height and \(t_1\) is the time to reach the maximum height. Since the vertical velocity is zero at the maximum height, we can use: \(v_y = v_{0y} - gt_1\) Find \(t_1\) and then substitute it into the equation for \(h\).
04

Calculate the horizontal distance

Lastly, we can find the horizontal distance, also known as the range, using the initial horizontal velocity and the time of flight: \(R = v_{0x}t\) Where \(R\) is the horizontal distance or range. Now we can answer the questions: (a) The maximum height the ball will rise is the value of \(h\) calculated in Step 3. (b) The time elapsed from the time the ball leaves the bat until it reaches the fielder is the value of \(t\) calculated in Step 2. (c) The distance from home plate the fielder will be when they catch the ball is the value of \(R\) calculated in Step 4.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A clump of soft clay is thrown horizontally from \(8.50 \mathrm{m}\) above the ground with a speed of \(20.0 \mathrm{m} / \mathrm{s} .\) Where is the clay after 1.50 s? Assume it sticks in place when it hits the ground.
After being assaulted by flying cannonballs, the knights on the castle walls ( \(12 \mathrm{m}\) above the ground) respond by propelling flaming pitch balls at their assailants. One ball lands on the ground at a distance of 50 m from the castle walls. If it was launched at an angle of \(53^{\circ}\) above the horizontal, what was its initial speed?
A vector is \(20.0 \mathrm{m}\) long and makes an angle of $60.0^{\circ} \mathrm{coun}-\( terclockwise from the \)y\( -axis (on the side of the \)-x$ -axis). What are the \(x\) - and \(y\) -components of this vector?
Two cars are driving toward each other on a straight and level road in Alaska. The BMW is traveling at \(100.0 \mathrm{km} / \mathrm{h}\) north and the VW is traveling at \(42 \mathrm{km} / \mathrm{h}\) south, both velocities measured relative to the road. At a certain instant, the distance between the cars is \(10.0 \mathrm{km} .\) Approximately how long will it take from that instant for the two cars to meet? [Hint: Consider a reference frame in which one of the cars is at rest. \(]\)
In each of these, the \(x\) - and \(y\) -components of a vector are given. Find the magnitude and direction of the vector. (a) $A_{x}=-5.0 \mathrm{m} / \mathrm{s}, A_{y}=+8.0 \mathrm{m} / \mathrm{s} .\( (b) \)B_{x}=+120 \mathrm{m}$ $B_{y}=-60.0 \mathrm{m} .(\mathrm{c}) C_{x}=-13.7 \mathrm{m} / \mathrm{s}, C_{y}=-8.8 \mathrm{m} / \mathrm{s} .(\mathrm{d}) D_{x}=$ \(2.3 \mathrm{m} / \mathrm{s}^{2}, D_{y}=6.5 \mathrm{cm} / \mathrm{s}^{2}\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free