A charged pion can decay either into a muon or an electron. The two decay modes of a \(\pi^{-}\) are: \(\pi^{-} \rightarrow \mu^{-}+\bar{v}_{\mu}\) and \(\pi^{-} \rightarrow \mathrm{e}^{-}+\bar{v}_{\mathrm{e}} .\) Write the two decay modes for the \(\pi^{+}\) [Hint: \(\pi^{+}\) is the antiparticle of $\pi^{-} .$ Replace each particle in the decay reaction with its corresponding antiparticle.]

Short Answer

Expert verified
Answer: The decay modes of a \(\pi^{+}\) are: 1. \(\pi^{+} \rightarrow \mu^{+}+v_{\mu}\) 2. \(\pi^{+} \rightarrow \mathrm{e}^{+}+v_{\mathrm{e}}\)

Step by step solution

01

Determine the antiparticles in the first decay mode

To find the decay mode of the \(\pi^{+}\), we first consider the first decay mode of the \(\pi^{-}\) and replace each particle with its corresponding antiparticle: - \(\pi^{-} \rightarrow\) antiparticle: \(\pi^{+}\) - \(\mu^{-} \rightarrow\) antiparticle: \(\mu^{+}\) - \(\bar{v}_{\mu} \rightarrow\) antiparticle: \(v_{\mu}\)
02

Write decay mode 1 for \(\pi^{+}\)

Using the antiparticles determined in Step 1, we rewrite the first decay mode of the \(\pi^{-}\) for the \(\pi^{+}\): \(\pi^{+} \rightarrow \mu^{+}+v_{\mu}\)
03

Determine the antiparticles in the second decay mode

Next, we consider the second decay mode of the \(\pi^{-}\) and replace each particle with its corresponding antiparticle: - \(\pi^{-} \rightarrow\) antiparticle: \(\pi^{+}\) - \(\mathrm{e}^{-} \rightarrow\) antiparticle: \(\mathrm{e}^{+}\) - \(\bar{v}_{\mathrm{e}} \rightarrow\) antiparticle: \(v_{\mathrm{e}}\)
04

Write decay mode 2 for \(\pi^{+}\)

Using the antiparticles determined in Step 3, we rewrite the second decay mode of the \(\pi^{-}\) for the \(\pi^{+}\): \(\pi^{+} \rightarrow \mathrm{e}^{+}+v_{\mathrm{e}}\) The two decay modes for the \(\pi^{+}\) are: 1. \(\pi^{+} \rightarrow \mu^{+}+v_{\mu}\) 2. \(\pi^{+} \rightarrow \mathrm{e}^{+}+v_{\mathrm{e}}\)

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