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Chapter 4: Problem 27

What is the acceleration of an automobile of mass $1.40 \times 10^{3} \mathrm{kg}\( when it is subjected to a forward force of \)3.36 \times 10^{3} \mathrm{N} ?$

Short Answer

Expert verified
Answer: The acceleration of the automobile is approximately \(2.4 \, \mathrm{m/s^2}\).

Step by step solution

01

Write down the given values

The mass of the automobile is given as \(1.40 \times 10^{3}\mathrm{kg}\), and the forward force acting upon it is \(3.36 \times 10^{3}\mathrm{N}\).
02

Use Newton's Second Law of Motion

Newton's second law states that the force acting on an object is equal to its mass times its acceleration: $$F = m \cdot a$$
03

Rearrange the equation for acceleration

To find the acceleration, we need to rearrange the equation to solve for a: $$a = \frac{F}{m}$$
04

Plug in the given values and solve for acceleration

Now we can plug in the given values into the equation: $$a = \frac{3.36 \times 10^{3}\mathrm{N}}{1.40 \times 10^{3}\mathrm{kg}}$$ […]
05

Calculate the acceleration

When we plug in the values and calculate the result: $$a \approx 2.4 \, \mathrm{m/s^2}$$ The acceleration of the automobile is approximately \(2.4 \, \mathrm{m/s^2}\).

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Most popular questions from this chapter

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