An airline executive decides to economize by reducing the amount of fuel required for long-distance flights. He orders the ground crew to remove the paint from the outer surface of each plane. The paint removed from a single plane has a mass of approximately \(100 \mathrm{kg} .\) (a) If the airplane cruises at an altitude of \(12000 \mathrm{m},\) how much energy is saved in not having to lift the paint to that altitude? (b) How much energy is saved by not having to move that amount of paint from rest to a cruising speed of $250 \mathrm{m} / \mathrm{s} ?$

Short Answer

Expert verified
Question: Calculate the energy savings from not having to lift 100 kg of paint to a cruising altitude of 12,000 m and not having to move the paint from rest to a cruising speed of 250 m/s. Answer: The energy saved in not having to lift the paint to the cruising altitude is 11,760,000 J, and the energy saved by not having to move the paint to the cruising speed is 3,125,000 J.

Step by step solution

01

Part (a) Gravitational Potential Energy Saved by Not Lifting the Paint

1. Determine the mass of the paint, the acceleration due to gravity, and the altitude. The mass of the paint is given as \(m = 100\,\mathrm{kg}\). The acceleration due to gravity is a constant, \(g = 9.8\,\mathrm{m/s^2}\). The altitude is given as \(h = 12000\,\mathrm{m}\). 2. Calculate the gravitational potential energy saved by not having to lift the paint to the altitude. To find the gravitational potential energy, we use the formula: \(PE = m \cdot g \cdot h\). Plug in the values we found in step 1 to get \(PE = (100\,\mathrm{kg}) \cdot (9.8\,\mathrm{m/s^2}) \cdot (12000\,\mathrm{m})\). 3. Evaluate the expression to find the energy saved. \(PE = 100\,\mathrm{kg} \cdot 9.8\,\mathrm{m/s^2} \cdot 12000\,\mathrm{m} = 11,760,000\,\mathrm{J}\). The energy saved in not having to lift the paint to the cruising altitude is \(11,760,000\,\mathrm{J}\).
02

Part (b) Kinetic Energy Saved by Not Having to Move the Paint to Cruising Speed

1. Determine the mass of the paint and the cruising speed. The mass of the paint is the same as part (a), \(m = 100\,\mathrm{kg}\). The cruising speed is given as \(v = 250\,\mathrm{m/s}\). 2. Calculate the kinetic energy saved by not having to move the paint from rest to the cruising speed. To find the kinetic energy, we use the formula: \(KE = \frac{1}{2}m \cdot v^2\). Plug in the values we found in step 1 to get \(KE = \frac{1}{2}(100\,\mathrm{kg}) \cdot (250\,\mathrm{m/s})^2\). 3. Evaluate the expression to find the energy saved. \(KE = 100\,\mathrm{kg} \cdot \frac{1}{2} \cdot (250\,\mathrm{m/s})^2 = 3,125,000\,\mathrm{J}\). The energy saved by not having to move that amount of paint from rest to a cruising speed of \(250\,\mathrm{m/s}\) is \(3,125,000\,\mathrm{J}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A shooting star is a meteoroid that burns up when it reaches Earth's atmosphere. Many of these meteoroids are quite small. Calculate the kinetic energy of a meteoroid of mass \(5.0 \mathrm{g}\) moving at a speed of $48 \mathrm{km} / \mathrm{s}$ and compare it to the kinetic energy of a 1100 -kg car moving at \(29 \mathrm{m} / \mathrm{s}(65 \mathrm{mi} / \mathrm{h})\).
How much work must Denise do to drag her basket of laundry of mass $5.0 \mathrm{kg}\( a distance of \)5.0 \mathrm{m}$ along a floor, if the force she exerts is a constant \(30.0 \mathrm{N}\) at an angle of \(60.0^{\circ}\) with the horizontal?
Jorge is going to bungee jump from a bridge that is \(55.0 \mathrm{m}\) over the river below. The bungee cord has an unstretched length of \(27.0 \mathrm{m} .\) To be safe, the bungee cord should stop Jorge's fall when he is at least $2.00 \mathrm{m}\( above the river. If Jorge has a mass of \)75.0 \mathrm{kg},$ what is the minimum spring constant of the bungee cord?
Dirk pushes on a packing box with a horizontal force of \(66.0 \mathrm{N}\) as he slides it along the floor. The average friction force acting on the box is \(4.80 \mathrm{N} .\) How much total work is done on the box in moving it $2.50 \mathrm{m}$ along the floor?
When the spring on a toy gun is compressed by a distance \(x\), it will shoot a rubber ball straight up to a height of \(h .\) Ignoring air resistance, how high will the gun shoot the same rubber ball if the spring is compressed by an amount \(2 x ?\) Assume \(x<<h\)
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free