Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 6: Problem 67

In Section \(6.2,\) Rosie lifts a trunk weighing \(220 \mathrm{N}\) up $4.0 \mathrm{m} .\( If it take her \)40 \mathrm{s}$ to lift the trunk, at what average rate does she do work?

Short Answer

Expert verified
Answer: The average rate at which Rosie does work is 22 watts.

Step by step solution

01

Find the force exerted by Rosie

To calculate the force exerted by Rosie, we simply use the given weight of the trunk which is 220 N, as the weight is equal to the force exerted when lifting the trunk. Force = 220 N
02

Find the work done

Now, we can find the work done by multiplying the force exerted (220 N) with the distance lifted (4 m). Work = Force x Distance Work = 220 N × 4 m Work = 880 J
03

Calculate the average rate at which Rosie does work

As we have found the work done by Rosie, we can now calculate the average rate of work done by dividing the total work done by the time taken to lift(which is 40 s). Average rate of work = Work done / Time taken Average rate of work = 880 J / 40 s Average rate of work = 22 W The average rate at which Rosie does work while lifting the trunk is 22 watts.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Rachel is on the roof of a building, \(h\) meters above ground. She throws a heavy ball into the air with a speed \(v,\) at an angle \(\theta\) with respect to the horizontal. Ignore air resistance. (a) Find the speed of the ball when it hits the ground in terms of \(h, v, \theta,\) and \(g .\) (b) For what value(s) of \(\theta\) is the speed of the ball greatest when it hits the ground?
You shoot a \(51-\mathrm{g}\) pebble straight up with a catapult whose spring constant is \(320 \mathrm{N} / \mathrm{m} .\) The catapult is initially stretched by \(0.20 \mathrm{m}\). How high above the starting point does the pebble fly? Ignore air resistance.
A skier starts from rest at the top of a frictionless slope of ice in the shape of a hemispherical dome with radius \(R\) and slides down the slope. At a certain height \(h,\) the normal force becomes zero and the skier leaves the surface of the ice. What is \(h\) in terms of \(R ?\)
Emil is tossing an orange of mass \(0.30 \mathrm{kg}\) into the air. (a) Emil throws the orange straight up and then catches it, throwing and catching it at the same point in space. What is the change in the potential energy of the orange during its trajectory? Ignore air resistance. (b) Emil throws the orange straight up, starting \(1.0 \mathrm{m}\) above the ground. He fails to catch it. What is the change in the potential energy of the orange during this flight?
An airline executive decides to economize by reducing the amount of fuel required for long-distance flights. He orders the ground crew to remove the paint from the outer surface of each plane. The paint removed from a single plane has a mass of approximately \(100 \mathrm{kg} .\) (a) If the airplane cruises at an altitude of \(12000 \mathrm{m},\) how much energy is saved in not having to lift the paint to that altitude? (b) How much energy is saved by not having to move that amount of paint from rest to a cruising speed of $250 \mathrm{m} / \mathrm{s} ?$
See all solutions

Recommended explanations on Physics Textbooks

Conservation of Energy and Momentum

Read Explanation

Electricity and Magnetism

Read Explanation

Torque and Rotational Motion

Read Explanation

Physical Quantities And Units

Read Explanation

Engineering Physics

Read Explanation

Fields in Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free