The number of kilocalories per day required by a person resting under standard conditions is called the basal metabolic rate (BMR). (a) To generate 1 kcal, Jermaine's body needs approximately 0.010 mol of oxygen. If Jermaine's net intake of oxygen through breathing is 0.015 mol/min while he is resting, what is his BMR in kcal/day? (b) If Jermaine fasts for 24 h, how many pounds of fat does he lose? Assume that only fat is consumed. Each gram of fat consumed generates \(9.3 \mathrm{kcal}\)

Short Answer

Expert verified
kcal per minute = 1.5 kcal/min #tag_title# Step 2: Convert kcal/min to kcal/day #tag_content# To find out how many kilocalories Jermaine consumes in one day, we need to convert the rate from kcal/min to kcal/day: kcal per day = kcal per minute * minutes per day kcal per day = 1.5 kcal/min * (24 hours/day * 60 min/hour) kcal per day = 2160 kcal/day #tag_title# Step 3: Calculate weight loss from fasting #tag_content# To calculate the amount of weight Jermaine would lose after fasting for a day, we'll need to use the energy generated from consuming fat (9 kcal/g). First, we need to find out how many grams of fat Jermaine's body would burn to generate 2160 kcal: grams of fat burned = kcal consumed / kcal per gram of fat grams of fat burned = 2160 kcal / 9 kcal/g grams of fat burned = 240 g Therefore, Jermaine would lose 240 grams of weight from fat after fasting for a day. #Answer# Jermaine would lose 240 grams of weight from fat after fasting for a day.

Step by step solution

01

Calculate kcal consumed per minute

Given that Jermaine's body needs 0.010 mol of oxygen to generate 1 kcal, we can calculate how many kcal he consumes in one minute by multiplying his net intake of oxygen by the conversion factor: kcal per minute = Net intake of oxygen * kcal per mol of oxygen kcal per minute = 0.015 mol/min * (1 kcal/0.010 mol)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The bungee jumper of Example 6.4 made a jump into the Gorge du Verdon in southern France from a platform \(182 \mathrm{m}\) above the bottom of the gorge. The jumper weighed \(780 \mathrm{N}\) and came within \(68 \mathrm{m}\) of the bottom of the gorge. The cord's unstretched length is \(30.0 \mathrm{m}\) (a) Assuming that the bungee cord follows Hooke's law when it stretches, find its spring constant. [Hint: The cord does not begin to stretch until the jumper has fallen \(30.0 \mathrm{m} .]\) (b) At what speed is the jumper falling when he reaches a height of \(92 \mathrm{m}\) above the bottom of the gorge?
An ideal spring has a spring constant \(k=20.0 \mathrm{N} / \mathrm{m}\) What is the amount of work that must be done to stretch the spring \(0.40 \mathrm{m}\) from its relaxed length?
A 4.0 -kg block is released from rest at the top of a frictionless plane of length \(8.0 \mathrm{m}\) that is inclined at an angle of \(15^{\circ}\) to the horizontal. A cord is attached to the block and trails along behind it. When the block reaches a point \(5.0 \mathrm{m}\) along the incline from the top, someone grasps the cord and exerts a constant tension parallel to the incline. The tension is such that the block just comes to rest when it reaches the bottom of the incline. (The person's force is a nonconservative force.) What is this constant tension? Solve the problem twice, once using work and energy and again using Newton's laws and the equations for constant acceleration. Which method do you prefer? A 4.0 -kg block is released from rest at the top of a frictionless plane of length \(8.0 \mathrm{m}\) that is inclined at an angle of \(15^{\circ}\) to the horizontal. A cord is attached to the block and trails along behind it. When the block reaches a point \(5.0 \mathrm{m}\) along the incline from the top, someone grasps the cord and exerts a constant tension parallel to the incline. The tension is such that the block just comes to rest when it reaches the bottom of the incline. (The person's force is a nonconservative force.) What is this constant tension? Solve the problem twice, once using work and energy and again using Newton's laws and the equations for constant acceleration. Which method do you prefer?
A 69.0 -kg short-track ice skater is racing at a speed of $11.0 \mathrm{m} / \mathrm{s}$ when he falls down and slides across the ice into a padded wall that brings him to rest. Assuming that he doesn't lose any speed during the fall or while sliding across the ice, how much work is done by the wall while stopping the ice skater?
The escape speed from the surface of Planet Zoroaster is $12.0 \mathrm{km} / \mathrm{s} .$ The planet has no atmosphere. A meteor far away from the planet moves at speed \(5.0 \mathrm{km} / \mathrm{s}\) on a collision course with Zoroaster. How fast is the meteor going when it hits the surface of the planet?
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free