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Chapter 7: Problem 2

What is the momentum of an automobile (weight = \(9800 \mathrm{N})\) when it is moving at \(35 \mathrm{m} / \mathrm{s}\) to the south?

Short Answer

Expert verified
Answer: The momentum of the automobile is 35000 kg⋅m/s to the south.

Step by step solution

01

Convert weight to mass

Given the weight of the automobile is \(9800\,\mathrm{N}\), we can find its mass using the formula: \(weight = mass × gravity\). Here, gravity is approximately \(9.8\,\mathrm{m/s^2}\) (assuming Earth's surface). Therefore, the mass (m) of the automobile can be calculated by: \(m=\frac{weight}{gravity}=\frac{9800\,\mathrm{N}}{9.8\,\mathrm{m/s^2}}=1000\,\mathrm{kg}\)
02

Calculate momentum

Now that we have the mass of the automobile, we can calculate its momentum using the given velocity. The formula for momentum (p) is: \(p=mass × velocity\). The momentum of the automobile is: \(p=1000\,\mathrm{kg}\times35\,\mathrm{m/s}=35000\,\mathrm{kg\cdot m/s}\)
03

Express the result with the proper direction

The direction of the momentum is the same as that of the velocity, that is, south. Therefore, the momentum of the automobile when it is moving at \(35\,\mathrm{m/s}\) to the south is \(35000\,\mathrm{kg\cdot m/s}\) to the south.

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Most popular questions from this chapter

A projectile of mass \(2.0 \mathrm{kg}\) approaches a stationary target body at \(8.0 \mathrm{m} / \mathrm{s} .\) The projectile is deflected through an angle of \(90.0^{\circ}\) and its speed after the collision is $6.0 \mathrm{m} / \mathrm{s}$ What is the speed of the target body after the collision if the collision is perfectly elastic?
In the railroad freight yard, an empty freight car of mass \(m\) rolls along a straight level track at \(1.0 \mathrm{m} / \mathrm{s}\) and collides with an initially stationary, fully loaded boxcar of mass 4.0m. The two cars couple together on collision. (a) What is the speed of the two cars after the collision? (b) Suppose instead that the two cars are at rest after the collision. With what speed was the loaded boxcar moving before the collision if the empty one was moving at \(1.0 \mathrm{m} / \mathrm{s} ?\)
Verify that the SI unit of impulse is the same as the SI unit of momentum.
A 2.0-kg block is moving to the right at \(1.0 \mathrm{m} / \mathrm{s}\) just before it strikes and sticks to a 1.0-kg block initially at rest. What is the total momentum of the two blocks after the collision?
A sports car traveling along a straight line increases its speed from $20.0 \mathrm{mi} / \mathrm{h}\( to \)60.0 \mathrm{mi} / \mathrm{h} .$ (a) What is the ratio of the final to the initial magnitude of its momentum? (b) What is the ratio of the final to the initial kinetic energy?
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