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Chapter 8: Problem 14

A 124 -g mass is placed on one pan of a balance, at a point \(25 \mathrm{cm}\) from the support of the balance. What is the magnitude of the torque about the support exerted by the mass?

Short Answer

Expert verified
Answer: The magnitude of the torque exerted by the 124 g mass about the support is approximately 0.304 Nm.

Step by step solution

01

Convert mass to force

Using the gravitational force formula, F = mg, we can convert the mass given in the problem from grams to kilograms and then to a force. Mass: 124 g = 0.124 kg Gravity: g = 9.81 m/s^2 Now multiply the mass (in kg) by the gravitational constant: Force, F = (0.124 kg)(9.81 m/s^2) = 1.21764 N Now we have the force exerted by the mass.
02

Calculate the torque

Using the torque formula, torque = force x distance: Distance: 25 cm = 0.25 m (convert the distance from cm to meters) Now multiply the force (in N) by the distance (in meters): Torque = (1.21764 N)(0.25 m) = 0.30441 Nm The magnitude of the torque exerted by the mass about the support is approximately 0.304 Nm.

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