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Chapter 9: Problem 20

A woman's systolic blood pressure when resting is \(160 \mathrm{mm}\) Hg. What is this pressure in (a) \(\mathrm{Pa},\) (b) \(\mathrm{lb} / \mathrm{in}^{2}\) (c) atm, (d) torr?

Short Answer

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Question: A woman's systolic blood pressure when resting is 160 mm Hg. Convert this pressure to: (a) pascals (Pa) (b) pounds per square inch (lb/in²) (c) atmospheres (atm) (d) torr Answer: (a) 21331.52 Pa (b) 3.093888 lb/in² (c) 0.21052624 atm (d) 160 torr

Step by step solution

01

Convert mm Hg to Pa

Identify the conversion factor between mm Hg and Pa: 1 mm Hg ≈ 133.322 Pa Now, multiply the woman's systolic blood pressure in mm Hg by this conversion factor to convert it to pascals (Pa). 160 mm Hg × (133.322 Pa / 1 mm Hg) ≈ 21331.52 Pa
02

Convert mm Hg to lb/in²

Identify the conversion factor between mm Hg and lb/in² (psi): 1 mm Hg ≈ 0.0193368 lb/in² Now, multiply the woman's blood pressure in mm Hg by this conversion factor to convert it to pounds per square inch (lb/in²). 160 mm Hg × (0.0193368 lb/in² / 1 mm Hg) ≈ 3.093888 lb/in²
03

Convert mm Hg to atm

Identify the conversion factor between mm Hg and atm: 1 mm Hg ≈ 0.001315789 atm Now, multiply the woman's systolic blood pressure in mm Hg by this conversion factor to convert it to atmospheres (atm). 160 mm Hg × (0.001315789 atm / 1 mm Hg) ≈ 0.21052624 atm
04

Convert mm Hg to torr

There is a direct relationship between mm Hg and torr. 1 mm Hg = 1 torr So, the woman's systolic blood pressure in torr is the same as in mm Hg. 160 mm Hg = 160 torr In summary, the woman's systolic blood pressure when resting is: (a) 21331.52 Pa (b) 3.093888 lb/in² (c) 0.21052624 atm (d) 160 torr

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