An IV is connected to a patient's vein. The blood pressure in the vein has a gauge pressure of \(12 \mathrm{mm}\) Hg. At least how far above the vein must the IV bag be hung in order for fluid to flow into the vein? Assume the fluid in the IV has the same density as blood.

Short Answer

Expert verified
Answer: The IV bag must be hung at a minimum height of 0.151 meters (or 15.1 cm) above the vein for the fluid to flow into the patient's vein.

Step by step solution

01

Identify the given information

The gauge pressure in the patient's vein is 12 mm Hg. We also know that the density of blood is approximately the same as the fluid in the IV.
02

Convert the pressure

To make the calculation easier, let's convert the gauge pressure from mm Hg to Pascals (Pa). We can use the conversion: 1 mm Hg = 133.3 Pa. Therefore, the gauge pressure in the vein is: \(12 \mathrm{mm}\,\mathrm{Hg} \times 133.3\,\mathrm{Pa/mm}\,\mathrm{Hg} = 1599.6 \, \mathrm{Pa}\)
03

Apply Pascal's Law and the concept of pressure in a fluid column

According to Pascal's law, the pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid. Therefore, we can say: \(P_{fluid} = P_{vein}\). The pressure in a fluid column is given by the hydrostatic pressure equation: \(P = h\rho g\), where \(h\) is the height of the liquid column, \(\rho\) is the density, and \(g\) is the acceleration due to gravity.
04

Solve for height h

Since \(P_{fluid} = P_{vein}\), we can write the equation as: \(h\rho g = P_{vein}\). Now we have to solve for the height (h) at which the IV bag must be hung: \(h = \dfrac{P_{vein}}{\rho g}\) The density of blood (and IV fluid) is 1060 kg/m³. The acceleration due to gravity is approximately 9.81 m/s².
05

Calculate the height

Now we can use the values we obtained to calculate the minimum distance above the vein: \(h = \dfrac{1599.6\,\mathrm{Pa}}{ 1060\,\mathrm{kg/m^{3}} \cdot 9.81\,\mathrm{m/s^2}} \approx 0.151\,\mathrm{m}\) So, the IV bag must be hung at least 0.151 meters (or 15.1 cm) above the vein for fluid to flow into the vein.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

This table gives the terminal speeds of various spheres falling through the same fluid. The spheres all have the same radius. $$\begin{array}{llllllll}\hline m= & 5.0 & 11.3 & 20.0 & 31.3 & 45.0 & 80.0 & (\mathrm{g}) \\\ \hline v_{1}= & 1.0 & 1.5 & 2.0 & 2.5 & 3.0 & 4.0 & (\mathrm{cm} / \mathrm{s}) \\\\\hline\end{array}$$, Is the drag force primarily viscous or turbulent? Explain your reasoning.
At the surface of a freshwater lake the air pressure is 1.0 atm. At what depth under water in the lake is the water pressure 4.0 atm?
Atmospheric pressure is about \(1.0 \times 10^{5} \mathrm{Pa}\) on average. (a) What is the downward force of the air on a desktop with surface area $1.0 \mathrm{m}^{2} ?$ (b) Convert this force to pounds so you really understand how large it is. (c) Why does this huge force not crush the desk?
What keeps a cloud from falling? A cumulus (fair-weather) cloud consists of tiny water droplets of average radius \(5.0 \mu \mathrm{m} .\) Find the terminal velocity for these droplets at \(20^{\circ} \mathrm{C},\) assuming viscous drag. (Besides the viscous drag force, there are also upward air currents called thermals that push the droplets upward. (tutorial: rain drop)
(a) since the flow rate is proportional to the pressure difference, show that Poiseuille's law can be written in the form \(\Delta P=I R,\) where \(I\) is the volume flow rate and \(R\) is a constant of proportionality called the fluid flow resistance. (Written this way, Poiseuille's law is analogous to Ohm's law for electric current to be studied in Chapter \(18: \Delta V=I R,\) where \(\Delta V\) is the potential drop across a conductor, \(I\) is the electric current flowing through the conductor, and \(R\) is the electrical resistance of the conductor.) (b) Find \(R\) in terms of the viscosity of the fluid and the length and radius of the pipe.
See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free