A reconnaissance spacecraft circles the Moon at very low altitude. Calculate (a) its speed and \((b)\) its period of revolution. Take needed data for the Moon from Appendix C.

Short Answer

Expert verified
The spacecraft's speed and period of revolution around the moon can be calculated using the laws of circular motion in combination with the gravitational force. The exact numerical values would depend on the values for the moon's mass, the moon's radius and the gravitational constant given in Appendix C.

Step by step solution

01

Calculation for speed

The speed, \(v\), of an object moving in a circle of radius \(r\) under the influence of a gravitational body of mass \(m\) is given by the equation \(v = \sqrt{G \cdot \frac{m}{r}}\) where G is the gravitational constant. From Appendix C, get the required values for r (radius of the moon plus altitude of spacecraft which is very low in this case so it can be approximated to the moon's radius), m (mass of moon), and G (gravitational constant). Plug these values into the equation to get the speed.
02

Calculation for period of revolution

The period of revolution, \(T\), around a gravitational body of mass \(m\) in a circle of radius \(r\) is given by the equation \(T = \frac{2\pi r}{v}\). With the already calculated speed, \(v\), and the radius, \(r\), plugged into this equation, the student can find the period of revolution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A comet moving in an orbit of eccentricity \(0.880\) has a speed of \(3.72 \mathrm{~km} / \mathrm{s}\) when it is most distant from the Sun. Find its speed when it is closest to the Sun.

A rocket is accelerated to a speed of \(v=2 \sqrt{g R_{\mathrm{E}}}\) near the Earth's surface and then coasts upward. (a) Show that it will escape from the Earth. ( \(b\) ) Show that very far from the Earth its speed is \(v=\sqrt{2 g R_{\mathrm{E}}}\).

The planet Mars has a satellite, Phobos, which travels in an orbit of radius \(9400 \mathrm{~km}\) with a period of 7 h 39 min. Calculate the mass of Mars from this information. (The mass of Phobos is negligible compared with that of Mars.)

It is conjectured that a "burned-out" star could collapse to a "gravitational radius," defined as the radius for which the work needed to remove an object of mass \(m\) from the star's surface to infinity equals the rest energy \(m c^{2}\) of the object. Show that the gravitational radius of the Sun is \(G M_{\mathrm{S}} / c^{2}\) and determine its value in terms of the Sun's present radius. (For a review of this phenomenon see "Black Holes: New Horizons in Gravitational Theory," by Philip C. Peters, American Scientist, September- October \(1974, \mathrm{p} .575 .)\)

Express the universal gravitational constant \(G\) that appears in Newton's law of gravity in terms of the astronomical unit \(\mathrm{AU}\) as a length unit, the solar mass \(M_{\mathrm{S}}\) as a mass unit, and the year as a time unit. \(\left(1 \mathrm{AU}=1.496 \times 10^{11} \mathrm{~m}, 1 \mathrm{M}_{\mathrm{S}}=1.99 \times\right.\) \(\left.10^{30} \mathrm{~kg}, 1 \mathrm{y}=3.156 \times 10^{7} \mathrm{~s} .\right)(b)\) What form does Kepler's third law (Eq. \(14-23\) ) take in these units?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free