A boat floating in fresh water displaces \(35.6 \mathrm{kN}\) of water. \((a)\) What weight of water would this boat displace if it were floating in salt water of density \(1024 \mathrm{~kg} / \mathrm{m}^{3} ?(b)\) Would the volume of water displaced change? If so, by how much?

Short Answer

Expert verified
The boat would displace approximately \(36415.39 \mathrm{kN}\) of saltwater. There would be no change in the volume of water displaced.

Step by step solution

01

Calculate Volume of Freshwater

First, calculate the volume \(V\) of fresh water displaced by the boat. Use the formula \(V = F / g \) where \(F\) is the buoyant force measured in newtons (N) and \(g\) is the acceleration due to gravity \(9.8m/s^2\). In this case, \(F\) is equal to \(35.6 \mathrm{kN}\), or \(35600 \mathrm{N}\). Therefore, \(V = 35600 / 9.8 \approx 3632.65 \mathrm{m}^{3}\).
02

Calculate Weight of Saltwater Displaced

Next, calculate the weight of the salt water displaced when the boat is floating in this salt water. The formula to use is \(W = \rho * V * g\) where \(\rho\) is the density of the water, \(V\) is the volume of the water displaced by the boat (from Step 1), and \(g\) is the acceleration due to gravity \(9.8m/s^2\). The density of salt water given is \(1024 \mathrm{~kg} / \mathrm{m}^{3}\), hence, \(W = 1024 * 3632.65 * 9.8 \approx 36415.39 \mathrm{kN}\).
03

Determine if Volume of Displaced Water Change

In terms of volume, a ship always displaces exactly its own volume of water; the type of water does not matter. This is because the buoyant force (the weight of the displaced fluid) equals the weight of the object in equilibrium. Thus the volume of water displaced does not change.

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