Using a soap solution for which the surface tension is \(0.025 \mathrm{~N} / \mathrm{m}\), a child blows a soap bubble of radius \(1.40 \mathrm{~cm} .\) How much energy is expended in stretching the soap surface?

Short Answer

Expert verified
The energy expended in stretching the soap surface is \(7.75e-5 Joules\).

Step by step solution

01

List the Given Information

The surface tension (T) is \(0.025 N/m\) and the radius (r) of the bubble is \(1.40 cm\), which is converted to meters it's \(0.014 m\)
02

Calculate the Change in Surface Area

A bubble has two layers, so the surface area has doubled. The total change in surface area (\(\Delta A\)) of a sphere of radius r is given by the equation \(\Delta A = 2 \times 4\pi r^2 \). Plugging in the values gives \(\Delta A = 2 \times 4 \times 3.1416 \times (0.014 m)^2 = 0.0031 m^2\).
03

Calculate the Work Done

The work done (or energy expended) in stretching the bubble is given by the equation \(Work = T \times \Delta A\). Plugging the values in gives; \(Work = 0.025 N/m \times 0.0031 m^2 = 7.75e-5 Joules\).

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