What must be the value of the speed parameter \(\beta\) if the Lorentz factor \(\gamma\) is to be \((a) 1.01 ?(b) 10.0 ?(c) 100 ?(d)\) \(1000 ?\)

Short Answer

Expert verified
The values of the speed parameter \(\beta\) corresponding to the Lorentz factor values of 1.01, 10.0, 100, and 1000 are approximately 0.141, 0.995, 0.99995, and 0.9999995 respectively.

Step by step solution

01

Calculate for \( \gamma = 1.01 \)

We substitute \( \gamma = 1.01 \) into the formula \( \beta = \sqrt{1 - (1/\gamma^{2})}\). When we do this, we get \( \beta = \sqrt{1 - (1/1.01^{2})}\). This simplifies to approximately \( \beta = 0.141 \).
02

Calculate for \( \gamma = 10.0 \)

We substitute \( \gamma = 10.0 \) into the formula \( \beta = \sqrt{1 - (1/\gamma^{2})}\). This simplifies to \( \beta = \sqrt{1 - (1/10^{2})}\), which simplifies to approximately \( \beta = 0.995 \).
03

Calculate for \( \gamma = 100 \)

We substitute \( \gamma = 100 \) into the formula \( \beta = \sqrt{1 - (1/\gamma^{2})}\). This simplifies to \( \beta = \sqrt{1 - (1/100^{2})}\), which simplifies to approximately \( \beta = 0.99995 \).
04

Calculate for \( \gamma = 1000 \)

We substitute \( \gamma = 1000 \) into the formula \( \beta = \sqrt{1 - (1/\gamma^{2})}\). This simplifies to \( \beta = \sqrt{1 - (1/1000^{2})}\), which simplifies to approximately \( \beta = 0.9999995 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a theory proposed by Albert Einstein in 1905, which revolutionized our understanding of space, time, and motion. Simply put, this theory states that the laws of physics are the same for all non-accelerating observers, and that the speed of light in a vacuum is constant, regardless of the motion of the light source or observer.

One of the most striking consequences of special relativity is the relationship between time, space, and speed. As an object moves faster, time literally slows down for it compared to an observer at rest - a concept known as time dilation. This theory has passed rigorous tests and is essential in understanding how objects behave at high speeds, particularly as they approach the speed of light. The solutions to the given exercise are direct applications of the formulas derived from this fascinating theory.
Speed of Light
In the realm of special relativity, the speed of light holds a central position. It is denoted by the letter 'c' and has a value of approximately 299,792,458 meters per second. This speed is the cosmic speed limit; no object with mass can accelerate to or exceed the speed of light.

What's truly intriguing is that the speed of light is the same for all observers, no matter their relative motion, which leads to many of the counterintuitive predictions of special relativity, such as time dilation and length contraction. It's this invariance of the speed of light that makes it possible to relate the Lorentz factor \( \gamma \) to velocities as fractions of the speed of light, expressed in the exercises through the speed parameter \( \beta \).
Time Dilation
Time dilation is a direct consequence of the constancy of the speed of light. According to special relativity, as an object's velocity increases relative to an observer, time appears to pass more slowly for that object from the observer's viewpoint. This phenomenon is not merely theoretical; it is confirmed by experimental evidence, including the observation of longer decay times for fast-moving particles.

Furthermore, time dilation has practical implications, like the need for corrections in the timing systems of GPS satellites, as their speeds alter the flow of time relative to clocks on the Earth's surface. A better understanding of time dilation can be seen in the calculated values of the speed parameter \( \beta \) for different Lorentz factors \( \gamma \), where a higher \( \gamma \) implies greater speeds and more pronounced time dilation effects.
Relativistic Velocity
Relativistic velocity is the velocity of an object moving close to the speed of light. At such high speeds, classical mechanics as described by Newtonian physics no longer apply, and the effects of special relativity become significant. This is when we must consider the Lorentz factor \( \gamma \) to accurately describe motion.

The Lorentz factor scales with the relative velocity \( \beta \) and becomes exceptionally large as \( \beta \) approaches 1, which signifies a velocity near the speed of light. The exercises illustrate this scaling, as \( \gamma \) increases from 1.01 to 1000, the corresponding \( \beta \) values approach closer to 1, indicating velocities nearing light speed. These relativistic velocities lead to the need for adjustments in the otherwise classical equations of motion, to account for the relativistic effects on time, length, and mass.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You wish to make a round trip from Earth in a spaceship, traveling at constant speed in a straight line for 6 months and then returning at the same constant speed. You wish further, on your return, to find the Earth as it will be 1000 years in the future. \((a)\) How fast must you travel? \((b)\) Does it matter whether or not you travel in a straight line on your journey? If, for example, you traveled in a circle for 1 year, would you still find that 1000 years had elapsed by Earth clocks when you returned?

Consider the following, all moving in free space: a \(2.0\) -eV photon, a \(0.40-\mathrm{MeV}\) electron, and a \(10-\mathrm{MeV}\) proton. \((a)\) Which is moving the fastest? (b) The slowest? ( \(c\) ) Which has the greatest momentum? \((d)\) The least? (Note: A photon is a light particle of zero mass.)

An alpha particle with kinetic energy \(7.70 \mathrm{MeV}\) strikes a \({ }^{14} \mathrm{~N}\) nucleus at rest. An \({ }^{17} \mathrm{O}\) nucleus and a proton are produced, the proton emitted at \(90^{\circ}\) to the direction of the incident alpha particle and carrying kinetic energy \(4.44 \mathrm{MeV}\). The rest energies of the various particles are: alpha particle, \(3730.4 \mathrm{MeV}\); \({ }^{14} \mathrm{~N}, 13,051 \mathrm{MeV} ;\) proton, \(939.29 \mathrm{MeV} ;{ }^{17} \mathrm{O}, 15,843 \mathrm{MeV}\) (a) Find the kinetic energy of the \({ }^{17} \mathrm{O}\) nucleus. (b) At what angle with respect to the direction of the incident alpha particle does the \({ }^{17} \mathrm{O}\) nucleus move?

An unstable high-energy particle enters a detector and leaves a track \(1.05 \mathrm{~mm}\) long before it decays. Its speed relative to the detector was \(0.992 c .\) What is its proper lifetime? That is, how long would it have lasted before decay had it been at rest with respect to the detector?

A particle moves along the \(x^{\prime}\) axis of frame \(S^{\prime}\) with a speed of \(0.43 c\). Frame \(S^{\prime}\) moves with a speed of \(0.587 c\) with respect to frame \(S .\) What is the measured speed of the particle in frame \(S ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free