Density is mass divided by volume. If the volume \(V\) is temperature dependent, so is the density \(\rho\). Show that the change in density \(\Delta \rho\) with change in temperature \(\Delta T\) is given by $$\Delta \rho=-\beta \rho \Delta T$$ where \(\beta\) is the coefficient of volume expansion. Explain the minus sign.

Short Answer

Expert verified
The change in density with temperature \(\Delta \rho\) is given by \(\Delta \rho=-\beta \rho \Delta T\). The minus sign indicates that the density decreases as the temperature increases, assuming a positive coefficient of volume expansion.

Step by step solution

01

Understanding the Basics

The basic formula for density is \(\rho=\frac{m}{V}\) where \(m\) is mass, \(V\) is volume, and \(\rho\) is density. Since the mass \(m\) does not change with temperature, we only need to consider volume \(V\) which is affected by temperature.
02

Incorporating Coefficient of Volume Expansion

The formula that incorporates the change in volume with temperature is \(V=V_0(1+\beta \Delta T)\) where \(V_0\) is the initial volume, \(\beta\) is the coefficient of volume expansion, and \(\Delta T\) is the change in temperature. If we substitute this back into the original density equation, we get \(\rho=\frac{m}{V_0(1+\beta \Delta T)}\). In other words, density decreases when volume increases due to increase in temperature.
03

Finding the Change in Density with Respect to Temperature

To find the change in density \(\Delta \rho\) with change in temperature \(\Delta T\), we differentiate the density equation with respect to \(T\). This gives us \(\Delta \rho=-\frac{m \beta}{V_0(1+\beta \Delta T)^2}\Delta T=-\beta \rho \Delta T\).
04

Explaining the Minus Sign

The negative sign in \(\Delta \rho=-\beta \rho \Delta T\) signifies that the density decreases as the temperature increases, given a positive value of \(\beta\). This is because as temperature increases, volume increases leading to decrease in density.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When the temperature of a copper penny (which is not pure copper) is raised by \(100 \mathrm{C}^{\circ}\), its diameter increases by \(0.18 \%\). Find the percent increase in \((a)\) the area of a face, \((b)\) the thickness, ( \(c\) ) the volume, and \((d)\) the mass of the penny. \((e)\) Calculate its coefficient of linear expansion.

(a) Prove that the change in rotational inertia \(I\) with temperature of a solid object is given by \(\Delta I=2 \alpha I \Delta T .(b)\) A thin uniform brass rod, spinning freely at 230 rev/s about an axis perpendicular to it at its center, is heated without mechanical contact until its temperature increases by \(170 \mathrm{C}^{\circ}\). Calculate the change in angular velocity.

If your doctor tells you that your temperature is \(310 \mathrm{~K}\), should you worry? Explain your answer.

Repeat Exercise 1, except choose the new temperature scale \(\mathrm{Q}\) so that absolute zero is \(0^{\circ} \mathrm{Q}\) and \(T_{\mathrm{bp} \text { , water }}-T_{\text {mp, water }}=\) \(100 \mathrm{Q}^{\circ} .(a)\) What is the conversion formula from Celsius to Q? (b) What is \(T_{\text {bp, water }}\) and \(T_{\text {mp,water }}\) in Q? ( \(c\) ) This scale actually exists. What is the official name?

The amplification or gain of a transistor amplifier may depend on the temperature. The gain for a certain amplifier at room temperature \(\left(20.0^{\circ} \mathrm{C}\right)\) is \(30.0\), whereas at \(55.0^{\circ} \mathrm{C}\) it is 35.2. What would the gain be at \(28.0^{\circ} \mathrm{C}\) if the gain depends linearly on temperature over this limited range?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free